There is a 2p walkdown it A takes 50Steps and B takes 75steps while the esclator is moving down given

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10 years agoHelpfull: Yes(2) No(0)
If A takes 1 step in one second, then B takes 3 steps in one second. If A takes t1 seconds to
take 50 steps, then B takes 150 steps in t1 seconds.
For B, to take 150 steps he requires t1 seconds,
then to take 75 steps he requires t1/2 seconds.
now use relative velocity
L - v*t1=50 (for first person)
L-v*t1/2=75(for second person)
S(escalator w.r.t ground)-s(person w.r.t escalator)=s1(person w.r.t ground)
S,s,s1 are the steps
now put the v*t1 from 1 into the second equation and u get
L- (L-50)/2=75
L+50=150
L=100;
10 years agoHelpfull: Yes(0) No(1)
See this link : http://totalgadha.com/mod/forum/discuss.php?d=915
9 years agoHelpfull: Yes(0) No(1)
There is a escalator and 2 persons move down it.A takes 50 steps and B takes 75 steps while the escalator is moving down.Given that the time taken by A to take 1 step is equal to time taken by B to take 3 steps.Find the no. of steps in the escalator while it is staionary?
9 years agoHelpfull: Yes(0) No(0)
Answer:- 100

An escalator is descending at constant speed. A walks down and takes 50 steps to reach the bottom. B runs down and takes 90 steps in the same time as A takes 10 steps.

let speed of A = 1 step/min
speed of esc = n steps/min
while A moves 50 steps, esc moves 50n steps.
Again, Atakes 10 steps in 10 mins. So B takes 90 steps in 10 mins, while esc moves 10n in the same time.
so, 50 + 50n = 90 + 10n
so, n=1
no. of stairs=100
9 years agoHelpfull: Yes(0) No(0)

There is a 2p walkdown it. A takes 50Steps and B takes 75steps while the esclator is moving down, given that the time taken by B to take 3Steps. find the no of steps escalator which in stationary?