325^325/125^n????

• Ans:216
  325^325/125^n
  325^325 = 325*325*325.................325 times
  and 125 = 5*5*5
  also 325 = 5*5*13 (2 fives)
  in 325 times 325 we have 5^(2*325) which we can write in (5^3)^216
  so the answer is 216
• 9 years agoHelpfull: Yes(5) No(7)
• On solving we get n= 216
  
• 9 years agoHelpfull: Yes(3) No(6)
• @KARTHIKEYANK .....can u please explain it properly
  
• 9 years agoHelpfull: Yes(1) No(0)
• 325^325/125^n
  The factor of 125= 5*5*5 = 5^3
  The factor of 325= 5*5*13 = (5^2)*(13^1)
  so Now 325^325 means = (5^2)^325 * (13^1)^325 = 5^650 * 13^325 ----1
  As 125^n = (5^3)^n =5^3n ----2
  so (1)/(2)
  = (5^650)*(13^325)/(5^3n)
  3*n=650
  n will be multiple of 3 then only it will divisible properly other wise not . 3*216=648 .but here if i do 3*217=651 but it is larger than 650
  Ans : 216
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• what is n???
  
• 9 years agoHelpfull: Yes(0) No(1)
• explain it properly
  
• 9 years agoHelpfull: Yes(0) No(1)
• answer is 216 as 325=5*5*13 and 125=5 *5* 5 so when we write 325^ 325 it is actually equal to 5^650*13^325 if this number is to be completely divisible by 125 that means 5^3n the power of 5 in 325 should be a multiple of 5 so that it is completely divisible by 5^3 we take 5^648 * 5^2 * 13^325/5^3n n comes out to be 216.
• 9 years agoHelpfull: Yes(0) No(0)