a team won 80% of the games if played.If played 5 more games of which if won 3 and lost 2.its lost % changed by 25%.how many games did it played overall

• say, total games played be x.
  now initially 80% games are won,so games won=4x/5
  and games lost=x/5
  later,5 more games are played out of which two r lost nd three are won
  so total no of games=x+5,won=4x/5+3 and lost=x/5+2
  also lost % changes by 25% i.e it becomes 25%
  so,x+10/5(x+5)*100=25
  and so,x=15
  
• 10 years agoHelpfull: Yes(12) No(5)
• X=15
  overall games=15+5=20
  
• 10 years agoHelpfull: Yes(5) No(0)
• Let total match b x
  (.2x+2)/(x+5) *100=25
  X=15
• 10 years agoHelpfull: Yes(3) No(4)
• Before 5 games team lost 20% of the games so ,suppose total games played be x
  so lost=x/5 and after 5 games it will become 25% so ,lost =25%(x+5)=(x+5)/4;
  so,(x+5)/4-x/5=2;
  so x=15;
• 10 years agoHelpfull: Yes(2) No(1)
• Sameer Saurabh Pls elaborate your solution
• 10 years agoHelpfull: Yes(1) No(0)
• (0.2x+2)=0.25(x+5)
  x=15 ans
• 10 years agoHelpfull: Yes(1) No(3)
• kindly give a proper full solution to it..so that one can understand
• 10 years agoHelpfull: Yes(1) No(0)
• Let total number of games initially played be n
  Team won 80% of the games => Lost games = 20% of n = n/5
  After that they played 5 more games in which they lost 2
  Now their loss
  (n+5)×25/100 = n/5 + 2
  n=15
  Therefore total games the team played=15+5 = 20
• 8 years agoHelpfull: Yes(1) No(0)