If 3*y+x>2 and x+2*y <3,
what can be said about the value of y?
a)y >-1
b)y =-1
c)y <-1
d)y = 1

• 1) y>-1
  
  multiplying second equation by -1 and adding with first equation we get
  y>-1
• 10 years agoHelpfull: Yes(16) No(0)
• 3Y+X>2
  -2Y-X>-3 MULTIPLY EQU.2 BY -1
  SOL= Y>-1
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• 3-2yy
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• sorry for the inconvenience occurred...
  3Y+X>2
  -2Y-X
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• Ans is:y>-1
  3*y+x>2-------1
  x+2*y
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• ans:y>-1
  solve both eqn simultaneously....
  
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• after solving
  3*y+x >2
  2*y+x >-3
  
  ---------
  y > -1
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• a)
  3y+x>2 .. eq1
  x+2y-3 ..eq3 \direction of < change to >
  add to equation 1
  u'll get
  y>-1
  
• 10 years agoHelpfull: Yes(0) No(1)
• When we put y>-1 in eq 2,then we need to put the same in eq 1.and thus the option is not satisfied.plz somebody explain me this.plz..urgent
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• if am taking y>-1 ex y=1 and x=0...in subs in eqn 1 we get 3>2 and eqn 2 we get 2
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• there r total 3 possible cases
  1st case- (1,1,5)
  3!/2!=3
  2nd case-(1,2,4)
  3!/1!=6
  3rd case-(1,3,3)
  3!/2!=6
  
  so 1st case+ 2nd case+ 3rd case=3+6+3=12
  so answer is 12.
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• y>-1 solving inequality then get y>-1
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• neglect x term in both sides..
  so ,3y>2 and 2y2/3 and y
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• 3y+x>2........1st and (x+2y-3.....2nd
  now adding 1st and 2nd equation then we get
  
  y>-1
  
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• multiply eq.2 with -1
  
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• 3*y+x>2 x+2*y2-x 2y2-x 2y-1
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