Elitmus
Exam
Numerical Ability
Log and Antilog
K=log base 3n,n <1000 n and k are whole no. How many value of k and n are possible.
A.5
B.6
C.7
D.none of these
Read Solution (Total 8)
-
- 7 values are possible
for k to be a whole no. n must be ... 1,3,9,27,81,243,729
n k
1 0
3 1
9 2
27 3
81 4
243 5
729 6.
so there are 7 value of k are possible - 10 years agoHelpfull: Yes(35) No(2)
- 7 will be the answer.
put the value of n=1
we get k=0 which is a whole no
again put the value of n=3
we get k=1 whole no
so the value of n will be in gp...
1,3,9,27,81,243,729
so 7 values of k being a whole no
- 10 years agoHelpfull: Yes(11) No(1)
- Answer: 6
- 10 years agoHelpfull: Yes(5) No(9)
- sorry ans shuld be 7 as n
- 10 years agoHelpfull: Yes(2) No(1)
- for k to be a whole no. n must be ... 1,3,9,27,81,243,729
7 values are possible.
- 10 years agoHelpfull: Yes(2) No(0)
- 7 possible value of k and n.
1,3,3^2,3^3,3^4,3^5,3^6. - 9 years agoHelpfull: Yes(1) No(0)
- 5 values are possible
for k to be a whole no. n must be ... 1,3,9,27,81
n k
1 0
3 1
9 2
27 3
81 4 - 10 years agoHelpfull: Yes(0) No(3)
- plz explain how putting n=3,, k is whole no???
- 10 years agoHelpfull: Yes(0) No(1)
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