sum of two no is 100 and sum of their reciprocal is 4/51 , if the smallest no is L then which of the following is true , ( i forgot the options)

• 85+15=100
  (1/85)+(1/15)=4/51
• 10 years agoHelpfull: Yes(2) No(0)
• (b)
• 10 years agoHelpfull: Yes(1) No(3)
• option a is right
  
• 10 years agoHelpfull: Yes(1) No(1)
• 4/51 * 100/100 = 400/5100 =100/1275
  Now 85 *15 = 1275
  which satisfies both the equations.
  Easiest way to solve it without solving algebraic equations.
  
• 10 years agoHelpfull: Yes(1) No(1)
• x+y=100
  
  1/x+1/y=4/51
  
  so xy=1275
  
  now factor of 1275=5*5*3*17
  
  so the lowest no. can be 5,3,25,17,15
  
  1. if l=5 then other no. will be 5*3*17
  2. if l=3 then other no. will be 5*5*17
  3. if l=15 then other no. will be 5*17
  4. if l=25 then other no. will be 3*17
  5. if l=17 then the other no. will be 5*5*3
  
  now looking at all the above condition
  condition 3 satisfy the equation
  
  x+y=100;
  
  15+85=100
• 7 years agoHelpfull: Yes(1) No(0)
• OPTIONS WERE:-
  A)L>0,B)17
• 10 years agoHelpfull: Yes(0) No(0)
• answer is
  o
• 10 years agoHelpfull: Yes(0) No(0)
• OPTIONS WERE:-
  A)L>0,B)1725,C)2549,D)L
• 10 years agoHelpfull: Yes(0) No(0)
• OPTIONS WERE:-
  A)L>0,B)1725,C)2549,D)L
• 10 years agoHelpfull: Yes(0) No(0)
• 0
• 10 years agoHelpfull: Yes(0) No(0)
• mukesh solution ke sath post karo
  
• 10 years agoHelpfull: Yes(0) No(0)
• ans first =85 and second=15
• 9 years agoHelpfull: Yes(0) No(0)
• x+y=100
  
  1/x+1/y=4/51
  
  so xy=1275
  
  now factor of 1275=5*5*3*17
  
  so the lowest no. can be 5,3,25,17
  
  1. if l=5 then other no. will be 5*3*17
  2. if l=3 then other no. will be 5*5*17
  3. if l=15 then other no. will be 5*17
  4. if l=25 then other no. will be 3*17
  
  now looking at all the above condition
  condition 3 satisfy the equation
  
  x+y=100;
  
  15+85=100
• 7 years agoHelpfull: Yes(0) No(0)