three single digit nos are in GP.If abs(x) for rea lx is absolute value of x (x if x is +ve/0 and -x if x is-ve),then the number of different possible values of abs(A+B-c) is
a)3 b)5 c)6 d)4

• b) 5
  series may be
  (1,2,4) & (4,2,1)
  (1,3,9) & (9,3,1)
  (2,4,8) & (8,4,2)
  (4,6,9) & (9,6,4)
  
  find abs(A+B-c) for these 8 series
  1, 5, 5, 11 , 2, 10, 1 , 11
  
  we get 5 different values (1,2,5,10,11)
• 9 years agoHelpfull: Yes(9) No(0)
• series is 1,3,9
  so abs(1+3-9)=5;
  BY alok
• 9 years agoHelpfull: Yes(5) No(2)
• RAKESH SOLUTION IS CORRECT
  
  Else
  
  1,2,4
  1,3,9
  2,4,8
  1,-2,4
  1,-3,9
  2,-4,8
  
  also gives abs(A+B-C)=1,5,2,11,10
  
  So total 5 Different Values Friends
• 9 years agoHelpfull: Yes(2) No(0)
• bcoz all the three no are single digit so the combination is b/w 1 to 9..
  and that is..1-2-4, 1-3-9, 2-4-8; and all give two values for abs(A+b-C)
  so total 6 values
• 9 years agoHelpfull: Yes(1) No(1)
• actuaaly answer is 5 accordimg to TCS pl anyone expl this...urgent
• 9 years agoHelpfull: Yes(0) No(1)
• sasank how do u choose that numbers 1,3,9
  
• 9 years agoHelpfull: Yes(0) No(1)
• @SASANK : please explain in detail abt 1,3,9 and why
• 9 years agoHelpfull: Yes(0) No(1)