TCS
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Numerical Ability
three single digit nos are in GP.If abs(x) for rea lx is absolute value of x (x if x is +ve/0 and -x if x is-ve),then the number of different possible values of abs(A+B-c) is
a)3 b)5 c)6 d)4
Read Solution (Total 7)
-
- b) 5
series may be
(1,2,4) & (4,2,1)
(1,3,9) & (9,3,1)
(2,4,8) & (8,4,2)
(4,6,9) & (9,6,4)
find abs(A+B-c) for these 8 series
1, 5, 5, 11 , 2, 10, 1 , 11
we get 5 different values (1,2,5,10,11) - 10 years agoHelpfull: Yes(9) No(0)
- series is 1,3,9
so abs(1+3-9)=5;
BY alok - 10 years agoHelpfull: Yes(5) No(2)
- RAKESH SOLUTION IS CORRECT
Else
1,2,4
1,3,9
2,4,8
1,-2,4
1,-3,9
2,-4,8
also gives abs(A+B-C)=1,5,2,11,10
So total 5 Different Values Friends - 10 years agoHelpfull: Yes(2) No(0)
- bcoz all the three no are single digit so the combination is b/w 1 to 9..
and that is..1-2-4, 1-3-9, 2-4-8; and all give two values for abs(A+b-C)
so total 6 values - 10 years agoHelpfull: Yes(1) No(1)
- actuaaly answer is 5 accordimg to TCS pl anyone expl this...urgent
- 10 years agoHelpfull: Yes(0) No(1)
- sasank how do u choose that numbers 1,3,9
- 10 years agoHelpfull: Yes(0) No(1)
- @SASANK : please explain in detail abt 1,3,9 and why
- 10 years agoHelpfull: Yes(0) No(1)
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