three single digit nos A,B,C are in GP.If abs(x) for real x is absolute value of x (x if x is +ve/0 and -x if x is-ve),then the number of different possible values of abs(A+B-C) is
a)3 b)5 c)6 d)4

• Ans is 5
  For(1,2,4) abs(1+2-4)=1
  For(1,3,9) abs(1+3-9)=5
  For(2,4,8) abs(2+4-8)=2
  For(1,-2,4) abs(1-2-4)=5
  For(1,-3,9) abs(1-3-9)=11
  For(2,-4,8) abs(2-4-8)=10
  So the different possible values are 1,2,5,10,11.
  
• 10 years agoHelpfull: Yes(7) No(2)
• answer is definitely 6 as possibilities are: 1 2 4, 1 3 9 , 2 4 8, also 4 6 9 are also in gp with r=3/2 and we can have negative terms also as -1 -2 -4,-1 -3 -9,-2 -4 -8,-4 -6 -9 now if we calculate diff value of a+b-c we will get eight values in which two are common so total six diff values is the answer
• 10 years agoHelpfull: Yes(3) No(0)
• ans 3
  1 2 4
  2 4 8
  1 3 9 are only possible single digit GP
• 10 years agoHelpfull: Yes(1) No(3)
• d)4
  one for all are +ve or negative
  2nd if a is -ve (same if both b and c is -ve)
  3rd if b is -ve (same if both a and c is -ve)
  4th if c is -ve (same if both b and a is -ve)
• 10 years agoHelpfull: Yes(0) No(2)