What least number must be subtracted from each of the numbers 17, 17, 34, 42 so that the ratio of first
two is the same as the ratio of the next two?
(A) 0 (zero) (B) 1
(C) 2 (D) 7

• question wrong
  it must me 14,17,34,42
  than answer will be:2
• 11 years agoHelpfull: Yes(13) No(0)
• let numbr be x
  (17-x)/(17-x)=(34-x)/(42-x)
  
  (17-x)(42-x)=( 34-x )(17-x)
  
  714 -578 =42x -34x
  x= 17
  
• 13 years agoHelpfull: Yes(10) No(47)
• numbers must be 14, 17, 34, & 42
  The solution is "2". If you subtract 2 from 14 and 17, you get 12 and 15. If you subtract 2 from 34 and 42, you arrive at 32 and 40. The ratios 12:15 and 32:40 both simplify to 4:5 (or 4/5 or .8).
• 11 years agoHelpfull: Yes(6) No(0)
• Answer is 2 , i don't know how..?
• 12 years agoHelpfull: Yes(4) No(7)
• the series is :- 14, 17, 34, 42
  and answer is :- (C) 2
• 7 years agoHelpfull: Yes(0) No(0)
• (14-x)/(17-x)=(34-x)/(42-x)
  (14-x)(42-x)=(34-x)(17-x)
  588-14x-42x+x2=578-34x-17x+x2
  10=5x
  x=10/5
  x=2
• 5 years agoHelpfull: Yes(0) No(0)