a, b, c are non negitive integers such that 28a+30b+31c = 365. a + b + c = ?

• 12 month = 365 days
  so a=7 (31 days month)
  b=4 ( 30 days month)
  c=1 (February)
  so answer= 7+4+1=12
• 10 years agoHelpfull: Yes(17) No(1)
• in a month there is one month with 28 days and four months with 30 days and seven months with 31 days .so a=1 and b=4 and c=7 so a+b+c=1+4+7=12
  
  
• 10 years agoHelpfull: Yes(6) No(0)
• 365 is nothing but the no of days in an year.
  There will be 4 months consist of 30 days. smilarly 1 month with 28 days and 7 months with 31 days.
  so 28*1+30*4+31*7=365
  Therefore a=1,b=4,c=7 a+b+c=12
• 10 years agoHelpfull: Yes(2) No(0)
• 12 is the answer
  because in a year there are 5 months with 31 days 4 months with 30 days and 1 month with 28 days
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• 12 it is just months of a year ...
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• 12 no. of days in an year is 365 nd no. of months having 28 days is 1 nd 31 days is 6 nd 30 days is 5 so, add them all we get 12 as ans
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• 12.
  28(1)+30(4)+31(7)=365..a,b and c are total no.of months in a year having 28,30 and 31 days respectively..
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• 12
  a,b,c are months
  a=1:feb;
  b=5:months having 30 days;
  c=6:months having 31 days;
  total=1 year:365 days
• 10 years agoHelpfull: Yes(0) No(0)
• lets compare with calendar........
  there is one month with 28 days therefore a=1
  there are are 4 months with 30 days,i.e., b=4
  there are 7 months with 31 days so c=7
  now add, we get a+b+c=1+4+7=12
• 10 years agoHelpfull: Yes(0) No(0)
• there is 365 days in a year
  a=1(feb),b=4(no.of month of 30 days),c=7(no.of month of 31 days)
  so a+b+c=1+4+7=12
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• 12
  calender concept will be used..a=1 b=6 c=5 therefore a+b+c=12
  
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• clearly 12 !
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• Here a,b,c represent months
  (a-feb)=1, (b-april,june,sept,nov)=4 & (c-rest others)=7
  Therefore, a+b+c=12
• 10 years agoHelpfull: Yes(0) No(0)