Three non negative numbers, X, Y and Z are such that the mean is M and the median is 5. If M is 10 more than the smallest number and 15 less than the biggest number, find the value of X+Y+Z.
(a) 15
(b) 5
(c) 20
(d) 30

• given median=5,so y=5
  x+y+z/3=10+z
  x+y+z/3=x-15
  solving 2 equations we get,
  x=25,y=5,z=0
  ans=30
• 10 years agoHelpfull: Yes(9) No(0)
• d)
  m is mean
  therefore,x+y+z=3m;
  suppose x is smallest and z is biggest therefore y is meadian i.e.5
  m=x+10
  m=z-15
  putting in 1
  we get m=10
  x+y+z=30
• 10 years agoHelpfull: Yes(4) No(0)
• Since mean=M, So, x+y+z=3M; median=5,=>y=5; M=x+10; M=y-15; Solving for M we get, M=10; So x+y+z=3M =3*10 = 30
• 10 years agoHelpfull: Yes(2) No(2)
• d.30
  m=x+10=>x=m-10
  m=z-15=>z=m+15 and y=5 as median
  (x+y+z)/3=m so replace x and z find m we get m=10.then we get x+y+z=30..
  ((m-10)+5+(m+15))/3=m
• 10 years agoHelpfull: Yes(1) No(0)
• (X+Y+Z)3 = M (or) X +Y +Z +3M Let Y be the middle value, then Y=5 X+Z=3M-5 X=M-10; Z=M+15; M-10+M+15=3M-5 M=10 X=0; Y=5; Z=25
• 10 years agoHelpfull: Yes(0) No(0)
• 30
  y=5
  m=x+10->x+y+z/3=x+10
  m=z-15->x+y+z/3=z-15
  solving we get 30
• 10 years agoHelpfull: Yes(0) No(0)