How many 8 digits numbers can be formed with repetition by using 1,2,3,4,5 which are divisible by 4

• for divisible by 4 the last two digit should be 12,24,32,44,52 ( 5 WAYS )
  
  rest 6 places can be filled in 5*5*5*5*5*5 = 5^6 ways
  
  so, total no. formed = 5 * 5^6 = 5^7
• 10 years agoHelpfull: Yes(37) No(0)
• Pls state the correct ans .......... All r providing ur own ans. So state the correct ans
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• the way of forming 8 digit no by using 5 digit and repitation is allowed r
  5*5*5*5*5*5*5*5=5^8
  but no should be divisible by 4, it is possible only when last 2 digit be divisible by 4.
  first find out 2digit no which divisile by 4 r 12 24 32 44 54 only so ans is
  5*5^6
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• 6*(5^6)
  As last 2 digits should be divisible by 4 so as to have divisible by 4
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• 12,24,32,44,52 are the only numbers at last two positions satisfying the given condition. Remaining digits can be written in 5^6 ways
  Hence, total no. of ways = 5 * 5^6
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• 5_5_5_5_5_5_ _
  12
  24
  32
  52
  44
  So 5^6*5
  =5^7
• 9 years agoHelpfull: Yes(0) No(0)