Three distinct single-digit numbers A,B and C are in Geometric Progression. If abs(x) for real x is the absolute value of x (x if x is positive or zero, and -x if x is negative), then the number of different possible values of abs(A+B+C) is

options:
a) 6
b) 4
c) 5
d) 3

• GPs may be
  1,2,4 ; -1,-2,-4 ; -1,2,-4 ; 1,-2,4
  1,3,9 ; -1,-3,-9 ; -1,3,-9 ; 1,-3,9
  2,4,8 ; -2,-4,-8 ; -2,4,-8 ; 2,-4,8
  now consider the first row of GPs,
  here abs(1+2+4)= abs(-1+(-2)+(-3)) AND abs(1+(-2)+3)=abs((-1)+2+(-3))
  similarly for other two rows of GPs mentioned.
  All in all, we have 2+2+2=6 DISTINCT values of abs(A+B+C)
  
  Therefore, correct option is a) 6
• 9 years agoHelpfull: Yes(21) No(13)
• b) 4
  GP may be
  1,2,4
  1,3,9
  2,4,8
  4,6,9
  value of abs(A+B+C) is 7,12,14,19
  4 differ values.
• 9 years agoHelpfull: Yes(15) No(22)
• 1) 5
  A,B,C may be
  (1,2,4) & (4,2,1)
  (1,3,9) & (9,3,1)
  (2,4,8) & (8,4,2)
  (4,6,9) & (9,6,4)
  
  find abs(A+B-c) for these 8 GPs
  1, 5, 5, 11 , 2, 10, 1 , 11
  
  we get 5 different values (1,2,5,10,11)
• 9 years agoHelpfull: Yes(13) No(3)
• The answer is 5 not 4. I don't have the solution but in the Online TCS Mock Test the answer for which marks are awarded is 5.
• 9 years agoHelpfull: Yes(6) No(3)
• Option (c) 5
  A,B,C may be
  (1,2,4) & (4,2,1)
  (1,3,9) & (9,3,1)
  (2,4,8) & (8,4,2)
  (4,6,9) & (9,6,4)
  
  find abs(A+B-c) for these 8 GPs
  1, 5, 5, 11 , 2, 10, 1 , 11
  
  we get 5 different values (1,2,5,10,11)
  
• 9 years agoHelpfull: Yes(5) No(1)
• 5
  Option (c) 5
  A,B,C may be
  (1,2,4) & (4,2,1)
  (1,3,9) & (9,3,1)
  (2,4,8) & (8,4,2)
  (4,6,9) & (9,6,4)
  
• 9 years agoHelpfull: Yes(4) No(1)
• 4?
  1 2 4
  1 3 9
  1 -2 4
  1 -3 9
• 9 years agoHelpfull: Yes(3) No(4)
• b) 4
  GP may be
  1,2,3
  1,3,9
  2,4,8
  4,6,9
  value of abs(A+B+C) is 6,12,14,19
  4 differ values.
  
• 9 years agoHelpfull: Yes(2) No(11)
• what correct ans
• 9 years agoHelpfull: Yes(1) No(0)
• GAGAN YEDIDA, Can you explain why did you use Abs(A+B-c) ?
  
  Thank You.
• 9 years agoHelpfull: Yes(1) No(0)
• 1,2,3
  1,3,9
  2,4,8
  4,6,9
  value of abs(A+B+C) is 6,12,14,19
  so 4
• 9 years agoHelpfull: Yes(1) No(1)
• case 1:(1,2,4)&(4,2,1) possible
  case 2:(2,4,8)&(8,4,2) possible
  case 3:(1,3,9)&(9,3,1) possible
  three different cases are possible because only single digits were allowed
  given:(a+b-c)
  taking each case values for a,b,c we get (1,5,5,11,2,10) possible values..here there are only 5 different values(1,5,2,11,10)....so ans is 5
• 6 years agoHelpfull: Yes(0) No(0)