You have to form a 6 digit even number with numbers from 1 to 7, the digit second to last should be even.

• ANS IS:720
  1 2 3 4 5 6 7
  - - - - - - -
  3C2*2! WILL FILL THE LAST 2 DIGITS
  REMAINING PLACES: 5C4*4!
  WE HAVE (5C4*4!)*(3C2*2!) =720
• 9 years agoHelpfull: Yes(16) No(0)
• digit to be even last digit has 3 chances ie:2 or 4 or 6
  digit 2nd to last should be also even so after filling last digit , this must have 2 chances.
  then first place will posses: 5 chances
  then second place will posses: 4 chances
  then third place will posses: 3 chances
  then next place will posses:2 chances
  finally product of chances are 5*4*3*2*2*3=720
  
  
• 9 years agoHelpfull: Yes(11) No(0)
• If repetition is allowed then 7*7*7*7*3*3 @ santosh
• 9 years agoHelpfull: Yes(4) No(0)
• nowhere its mentioned that repetition is not allowed.
  so the answer should be 7*7*7*7*3*7
• 9 years agoHelpfull: Yes(1) No(3)
• ans: 420
  bcz it is 6 digit num ------
  1st digit : we can take any number frm 1 to 7
  and second to last should be even 2,4 or 6
  so ans is 7*5p3 = 420
• 9 years agoHelpfull: Yes(1) No(0)
• What if repetition is allowed???
  
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 720
  
• 9 years agoHelpfull: Yes(0) No(0)
• if the second last is even then a total of 3 digits can be filled.
  if the number to be formed is odd then the 6th place has 4 digits that can be filled.
  hence, 2*3*4*5*3*4=720
• 9 years agoHelpfull: Yes(0) No(0)
• 135462
  second to last is even and the 6 digit is an even number
  
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• 2*3*4*5*3*2=720
• 9 years agoHelpfull: Yes(0) No(0)
• ans:720
  explanation:2*3*4*5*2*3=720
• 9 years agoHelpfull: Yes(0) No(0)
• ans 720
• 9 years agoHelpfull: Yes(0) No(0)