You have to form a 6 digit even number with numbers from 1 to 7 the digit second to last

digit to be even last digit has 3 chances ie:2 or 4 or 6
digit 2nd to last should be also even so after filling last digit , this must have 2 chances.
then first place will posses: 5 chances
then second place will posses: 4 chances
then third place will posses: 3 chances
then next place will posses:2 chances
finally product of chances are 5*4*3*2*2*3=720
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If repetition is allowed then 7*7*7*7*3*3 @ santosh
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nowhere its mentioned that repetition is not allowed.
so the answer should be 7*7*7*7*3*7
10 years agoHelpfull: Yes(1) No(3)
ans: 420
bcz it is 6 digit num ------
1st digit : we can take any number frm 1 to 7
and second to last should be even 2,4 or 6
so ans is 7*5p3 = 420
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What if repetition is allowed???
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ans is 720
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if the second last is even then a total of 3 digits can be filled.
if the number to be formed is odd then the 6th place has 4 digits that can be filled.
hence, 2*3*4*5*3*4=720
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135462
second to last is even and the 6 digit is an even number
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2*3*4*5*3*2=720
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ans:720
explanation:2*3*4*5*2*3=720
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ans 720
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You have to form a 6 digit even number with numbers from 1 to 7, the digit second to last should be even.