If certain number is divided by 5,3,2 successively, it will leave the reminder 0,2,1 respectively. If that same number is divided successively by 2,3,5 then what will be the reminder?
1) 4,0,1
2)1,0,4
3)4,2,0

• let the number is P.
  P=q1*5+0
  q1=q2*3+2
  q2=q3*5+1
  now put q3=1
  so, q2=3
  q1=3*3+2=11
  P=11*5=55
  now, 55%2=1(quotient=27)
  27%3=0(quotient=9)
  9%2=4
  so ans is 2)1,0,4
  
  
• 10 years agoHelpfull: Yes(8) No(2)
• 5 3 2
  0 2 1
  =>
  ((1*3 + 2)*5)+0=25
  25/2=1 /*Remainder*/
  12/3=0
  4/5=4
  Answer 2
• 10 years agoHelpfull: Yes(6) No(0)
• Logically,
  Given that if a no. is divided by 5 it gives reminder 0.
  From this we know that it should end with either 0 or 5.
  i.e either odd or even.
  
  If that number is now divided by 2, it should leave the reminder 1 or 0.
  so, obviously 1,0,4
• 10 years agoHelpfull: Yes(3) No(0)
• let the numbers be x y z
  2 divides z gives remainder 1
  so z= 3
  3 divides y and gives remiandeer as 2 and quotient as 3
  so y=11
  atlast 5 divides x and qotiont is 11
  so x is 55
  no divide 55 by 2 3 5
  ans
  1 0 4
• 10 years agoHelpfull: Yes(2) No(0)
• Let the Number be X
  x=q1*5+0
  q1=q2*3+2
  q2=q3*2+1
  Now just plug in 1 in q3
  therefore q2=3
  q1=11
  hence X=55
  now Divide 55/2=1 q=27
  27/3=0 q=9
  9/5=4 q=1
  Hence ans is 1,0,4
• 10 years agoHelpfull: Yes(1) No(0)
• no is 115 and ans is 1,0,4
• 10 years agoHelpfull: Yes(0) No(1)