Find the probability that a leap year chosen at random will contain 53 sundays 1 2 7 2 3 7

2/7=ans
Leap yr has 52 weeks + 2 odd days
Whc can be {sun,mon mon,tue tue,wed wed,thu thu,fri fri,sat sat,sun}
10 years agoHelpfull: Yes(16) No(0)
2/7
366/7=2 is remainder so, 2 odd days
so 2/7.
10 years agoHelpfull: Yes(5) No(0)
52 week + 2 odd day =366 day
(S,M) (MT)(TW)(WT)(TF)(FS)(SS)
ANS =2/7
9 years agoHelpfull: Yes(3) No(0)
2 odd day so 2/7
10 years agoHelpfull: Yes(1) No(1)
2/3
skcvbdkfv
10 years agoHelpfull: Yes(1) No(9)
52 weeks +2 days extra
so in 52 weeks there will be 52 sundays nd nxt one day lie on 2 days so probability is 2/7
9 years agoHelpfull: Yes(0) No(0)
In leap year,we have 366 days.
366/7=52Weeks+2days
we have already 52 sundays,mondays,etc.
then we have 2 days may be
{sunday,monday} , {monday,tuesday} , {tuesday,wednesday} ,....{saturday,sunday}
we have 2 possible chances out of 7. hence ans:2/7
7 years agoHelpfull: Yes(0) No(0)

Find the probability that a leap year chosen at random will contain 53 sundays.
1. 2/7
2. 3/7
3. 1/49
4. 1/7