A ladder 100 feet long is leaning against a wall. Its lower end is 60 foot from the bottom of the wall. The side of the largest cubical box that can be placed btw the wall and the ladder without disturbing the ladder is(to the nearest foot)

• Let the angle between ladder and Horizontal be A, and side of cuboid be s
  First find the wall height i.e, 80ft (because we need to find tanA)
  tanA=80/60=4/3.........(1)
  Now, tanA=s/60-s
  4/3=s/60-s
  s=34.2
• 10 years agoHelpfull: Yes(24) No(0)
• Let da side b x. Nw by similarly of triangle.
  80/60= (80-x)/80.
  Solving we get x=240/7=34.28
• 10 years agoHelpfull: Yes(10) No(2)
• let angle betn ladder with horizontal be A, den tanA=H/B=100/60=5/3
  again let be side of cube =s
  den tanA=s/60-s
  so 5/3=s/60-s
  so s=37.5 (ans)
• 10 years agoHelpfull: Yes(4) No(13)
• The other side is 40
  40/60=2/3
  hence the largest cube side would be (3/5)*40 or (2/5)*60
  therefore side of cube=24
• 10 years agoHelpfull: Yes(3) No(6)
• ANS IS 40.
  
• 10 years agoHelpfull: Yes(2) No(5)
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  (80-x)/x=x/(60-x) (AS tan(*)=p/b)
  x=34.28
• 10 years agoHelpfull: Yes(2) No(1)