The distance between 2 persons is 800m. If they start moving towards each other simultaneously at 10m/s and 15m/s, in how much time do they meet?

• they will meet after (800/25)=32 sec
  coz they are moving in relative velocity (10+15)=25m/s
• 9 years agoHelpfull: Yes(16) No(0)
• 
  32 minutes
• 9 years agoHelpfull: Yes(5) No(14)
• combined velocity is 25 m/s
  distance=800m
  time=800/25
  =32 sec
• 9 years agoHelpfull: Yes(5) No(0)
• they will be meet 32 sec
• 9 years agoHelpfull: Yes(1) No(0)
• In 1 hr both two person can complete 25 m/s.
  total distance is 800 m.
  so,
  time=distance/speed
  time=800/25=32 seconds
  
• 9 years agoHelpfull: Yes(1) No(0)
• 800/(10+15)=32sec
• 9 years agoHelpfull: Yes(1) No(0)
• 35
  800/10+15 =35
  
• 9 years agoHelpfull: Yes(0) No(6)
• 800/25=32
  25 because moving towards each other
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• 800/(10+15)=800/25=32
• 9 years agoHelpfull: Yes(0) No(0)
• 300 percent sure the answer will be 32
• 7 years agoHelpfull: Yes(0) No(1)
• very easy
  10+15=25
  Hence 800/25=32
• 7 years agoHelpfull: Yes(0) No(0)
• in 30s a will be 300m ahead and b will be 450m ahead(300+450=750)
  and in another 2s a will be 20m and b will be 30m (20+30=50)
  in 32s (750+50=800m)
  ans is 32s
• 7 years agoHelpfull: Yes(0) No(0)
• time=distance/relative speed
  =800/25
  =32sec
• 6 years agoHelpfull: Yes(0) No(0)
• t=d/s
  t=800/(10+15)=32sec
• 5 years agoHelpfull: Yes(0) No(0)