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In a reading room of a library there are 22 reading spots. Each reading spot consists of a round table with 9 chairs placed around it. In each table different numbers of people are seated. If in all there are 36 readers how many reading spots will be left out without at least 1 reader?
a) 8
b) 12
c) 16
d) None of these
Read Solution (Total 17)
-
- Since at least there can be 1 reader in a table so the following case is possible
1st table- 9 members
2nd table- 8 members
3rd table- 7 members
4th table- 6 members
5th table - 5 members
6th table -1 member
therefore 9+8+7+6+5+1=36 and no. of tables are 6. so, no. of remaining tables are 22-6 = 16(ans). - 10 years agoHelpfull: Yes(17) No(0)
- 1,2,3,4,5,6,7,8, rest all empty. i.e. 22-8=14
- 10 years agoHelpfull: Yes(7) No(6)
- d - non of these... coz I guess answer willb 18
- 10 years agoHelpfull: Yes(3) No(4)
- sorry frnds answer is 14 so option d is correct
- 10 years agoHelpfull: Yes(3) No(2)
- 14. so the answer is d
- 10 years agoHelpfull: Yes(3) No(0)
- different no of people means
assume 9+8+7+6+5+1=36
so 22-6=16 - 10 years agoHelpfull: Yes(3) No(0)
- Ans:d)None of these
readers are arranged in the each reading spots 1,2,3,4,5,6,7,8
hence 8 tables are filled.(36 readers)
22-8=14
- 10 years agoHelpfull: Yes(2) No(1)
- Since at least there can be 1 reader in a table so the following case is possible
1st table- 8 members
2nd table- 7 members
3rd table- 6 members
4th table- 5 members
5th table - 4 members
6th table - 3 members
7th table - 2 members
8th table - 1 member
therefore 8+7+6+5+1=36 and no. of tables are 5. so, no. of remaining tables are 22-5 = 17(ans). - 10 years agoHelpfull: Yes(2) No(3)
- 16
As let's consider worst case scenario
9 on t1
8 on t2
7
6
5
1 so
16 tables remain - 10 years agoHelpfull: Yes(1) No(0)
- since different number of people are seated since atleast1 reader should not be common 1 reader should not present as common in each reading spot---=arrange 9 difeerent people in 4 reading spots =9*4=36 and remaining are 22-4=18 so d is answer
- 10 years agoHelpfull: Yes(1) No(0)
- 9,8,7,6,5,1 so 6 table is filled ans is 22-6=16 option 'c'
- 10 years agoHelpfull: Yes(0) No(2)
- answer is 16. :)
- 10 years agoHelpfull: Yes(0) No(2)
- Sum of readers is 36.
Sum of 1,2,3,4,5,6,7,8 = n(n+1)/2 = 8*9/2 = 36
- 10 years agoHelpfull: Yes(0) No(0)
- ans:C (16)
- 10 years agoHelpfull: Yes(0) No(0)
- d)22-8=14
total 22, 8 occupied - 10 years agoHelpfull: Yes(0) No(0)
- 1st table- 8 members
2nd table- 7 members
3rd table- 6 members
4th table- 5 members
5th table - 4 members
6th table - 3 members
7th table - 2 members
8th table - 1 member
so 8+7+6+5+4+3+2+1=36.
now 22-8=14 ans. - 10 years agoHelpfull: Yes(0) No(0)
- ans is: 16
assume in 1st spot there is 1 reader,2nd spot there is 2 readers , similarly until 8 spots there will be a total of 36 readers.
22-8=16
hence 16 is the ans - 10 years agoHelpfull: Yes(0) No(1)
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