2 vehicles A and B leave for city Y from city X. A overtakes B at 10.30 am and reaches city X at 12.00 pm. It waits for 2 hours and returns to city Y. On its way it meets B at 3 pm and reaches city at 5 pm. B reaches city X, waits for one hour and returns to city Y. After how many hours will B reach city Y from the time A overtook him for the first time?

• Let total distance be 60m.
  A covers that sixty metres in 3hrs such that 20m in 1hr.
  when a overtakes b then they were half way means 30m and when they again meet then they were on 40m. such that b covers 10m in 4.30hrs and b have to cover 90m to reach city Y again.
  so (4.5*9)+1hr(b waits for one hour)= 41.5hrs
  41.5 hrs is the answer
• 9 years agoHelpfull: Yes(23) No(2)
• A start at 2 pm. A meet 3 pm to B . A reach at 5 pm total time taken is 3 hours hence after one hour A meet B i.e. it covers 1/3 distance in 1 hour .Therefore B complete (2/3)-(1/2)=1/6 distance in 4.5hours.Hence B 27hours to complete the distance from x to y .Hence time taken by B for 1/3 distance and 1 complete distance i.e.=4/3. Hence time to reach B at y is 9+1+27=37 hours from 3pm.
  Hence after 37-2=35 hours is answer
• 9 years agoHelpfull: Yes(1) No(3)
• can you explain me how it is 40m when they meet again
• 9 years agoHelpfull: Yes(1) No(2)
• 41.5hrs
  let total distance from x to y be 60km
  then calculate a and b speed;
  a=90/3;
  b=10/3;
  hence calculate the time=41.5hrs
  
• 9 years agoHelpfull: Yes(0) No(4)
• a's part is understandable,,,but how to proceed to b's part of the question,,,
  
• 9 years agoHelpfull: Yes(0) No(1)
• why 60 m is the distance?
• 9 years agoHelpfull: Yes(0) No(0)
• olkMT$647LIQ
  A can do a piece of work in 10 days, while B can alone do it in 15 days. They work together for 5 days and the rest of the work is done by C in 2 days. If they get Rs.450 ... A train leaves station X at 5 am and reaches station Y at 9 am. Anoth
• 9 years agoHelpfull: Yes(0) No(0)
• please give me the correct answer.
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