TCS
Company
Numerical Ability
Number System
three distinct single digit numbers A,B,C are in GP. If abs(x) for real x is the absolute value of x(x if x is +ve or zero, -x if x is -ve), then the number of different possible values of abs(A+B-C) is:
1) 5
2) 4
3) 6
4) 3
Read Solution (Total 9)
-
- 1) 5
A,B,C may be
(1,2,4) & (4,2,1)
(1,3,9) & (9,3,1)
(2,4,8) & (8,4,2)
(4,6,9) & (9,6,4)
find abs(A+B-c) for these 8 GPs
1, 5, 5, 11 , 2, 10, 1 , 11
we get 5 different values (1,2,5,10,11) - 10 years agoHelpfull: Yes(50) No(6)
- @rakesh how 4,6,9 will be in gp?
- 10 years agoHelpfull: Yes(8) No(5)
- @rakesh why didn't u consider the negative numbers like (-4,-2,-1) they are also in g.p ......plz reply
- 10 years agoHelpfull: Yes(3) No(0)
- 6 is ans
1 2 4
2 4 8
1 3 9
-1 -2 -4
-2 -4 -8
-1 -3 -9 - 10 years agoHelpfull: Yes(2) No(10)
- @HIMA:
In mathematics, a geometric progression (also inaccurately known as a geometric series) is a sequence of numbers such that the quotient of any two successive members of the sequence is a constant called the common ratio of the sequence.
a geometric sequence can be written as:
aq^0=a, aq^1=aq, aq^2, aq^3, ... where q ≠ 0, q is the common ratio and a is a scale factor.
Ex : (4/6) = (6/9) = 2/3.
(9/6) = (6/4) = 3/2. - 10 years agoHelpfull: Yes(1) No(0)
- rakesh is absolutely right
- 10 years agoHelpfull: Yes(0) No(4)
- 2) 4
For a set of +ve value ,there should be only 2 sets of solutions->
1. if the gp is in the increasing pattern . e.g.- AC
AND ,same things follows for the -ve set of values.
so total no. of diffrent values are: 4 - 9 years agoHelpfull: Yes(0) No(0)
- answer is 5
rakesh is right plus if u consider negative value and put in the equation abs(A+B-C) u will
get the same result as before - 9 years agoHelpfull: Yes(0) No(0)
- which is the correct answer??
- 9 years agoHelpfull: Yes(0) No(0)
TCS Other Question