. If a man walks at rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at rate of 6 kmph,he reaches the station 5 minutes before the arrival of train. Find the distance covered by him to reach the station. [IET] 1)8 km 2)6.5 km 3)6 km 4)7 km

• t1=d/5
  t2=d/6
  t1-t2=(7+5) = 12min = 0.2hrs
  d/5 - d/6 = 0.2
  d=6 km
  OPTION 3.
• 10 years agoHelpfull: Yes(52) No(0)
• guys there is a simple frmula for such kind of questions where time interval matters
  (S1*S2)/(S2-S1)* time interval
  for example
  
  
  (6*5)(6-5)*(12/60)
  
  so ans will be 6km .
  
  
• 10 years agoHelpfull: Yes(17) No(1)
• D=[(7+5)/60](5*6)/(6-5)= 6 km
• 10 years agoHelpfull: Yes(7) No(0)
• Let d be initial distance and t be initial time
  d/5=t+7/60-->d=5t+7/12.....(1)
  d/6=t-5/60-->d=6t-5/10.....(2)
  from 1 & 2
  5t+7/12=6t-5/10
  t=13/12
  Putting the value of t in equ 1
  d/5=13/12+7/60
  d/5=72/60
  d=6km----------->Ans
  
  
• 10 years agoHelpfull: Yes(4) No(0)
• Let the required distance be Xkm.
  
  The total time difference between two events is 12 mins i.e=1/5 hr
  
  X/6-X/5=1/5
  
  6X-5X=6
  
  X=6km.
• 10 years agoHelpfull: Yes(4) No(0)
• LCM of 5 and 6=30.
  now diff of time = (30/5) - (30/6) = 1 hour
  so , 30km diff is = 1 hour = 60 mint
  so x km diff = 12 mint.
  i.e. 6 km.
• 10 years agoHelpfull: Yes(3) No(0)
• 5*(t+7)=6*(t-5)
  t=65
  thus D=6*(65-5)= 360
  thus D=6KM hint: (360/6)
• 10 years agoHelpfull: Yes(2) No(0)
• speed=distance/time
  t1=60*6/5=72
  t2=60*6/6=60
  t1-t2=12mins
  7+5=12mins
  Ans=6
• 10 years agoHelpfull: Yes(2) No(0)
• lets take time required is x hours
  d=5*(x+7/60)--i
  d=6*(x-5/60)--ii
  solve these two equations
  d=6km
• 10 years agoHelpfull: Yes(2) No(1)
• required distance=(product of two speed/difference of two speed)*difference between arrival time
  product of two speed=5*6=30 km/hr
  difference of two speed=6-5=1 km/hr
  diffrence between arrival time=(7+5)mins=12/60hr
  therefore distance=(6*5)/5=6km
  
  
• 10 years agoHelpfull: Yes(2) No(0)
• Let the required distance be x km.
  Differeiice in the times taken at two sneeds =12 min =1/5 hr
  x5−x6=15⇔6x−5x=6⇔x=6
  Hence, the required distance is 6 km.
• 10 years agoHelpfull: Yes(1) No(0)
• 6.5 km because of distance same in two cases but speed is different so d=s*t. Using this formula
• 10 years agoHelpfull: Yes(1) No(3)
• 5*6/6-5 * ( 7+5/60)=6 ans
• 9 years agoHelpfull: Yes(1) No(1)
• the answer is 6 km
• 9 years agoHelpfull: Yes(1) No(0)
• Let the required distance be x km.
  Difference in the times taken at two speeds =12 min =1/5 hr
  x5−x6=15⇔6x−5x=6⇔x=6
  Hence, the required distance is 6 km
• 9 years agoHelpfull: Yes(0) No(0)