if (AT)^2 = PEA , then what is P+E+A ?

• Answer is:10
  
  (19)^2=361
  so, 3+6+1=10
• 9 years agoHelpfull: Yes(22) No(7)
• place of A=1(in alphabetical order) and T=20(in alphabetical order)
  then we add A+T=21,21*21=441(PEA),P+E+A=9.
  OR T-A=19,19*19=361(PEA),THEN P+E+A=10.
  OR P*T=20,20*20=400(PEA),THEN P+E+A=4.
  SINCE OPTION IS NOT GIVEN SO YOU CAN TAKE ANY ONE OF THEM.
  
  
• 9 years agoHelpfull: Yes(10) No(6)
• A=1
  T=20
  AT=A*T=1*20=20
  (20)^2=400
  So,P=4
  E=0
  A=0
  P+E+A=4+0+0=4
  Ans is 4
• 9 years agoHelpfull: Yes(7) No(0)
• AT=19 how is it ???can anyone explain??
• 9 years agoHelpfull: Yes(6) No(0)
• (AT)^2= (1*19)^2=(19)^2=361
  P=3
  E=6
  A=1
  P*E*A=3*6*1
  P+E+A=3+6+1=10
  So,The ans is 10
  
• 9 years agoHelpfull: Yes(5) No(0)
• (19)^2=361
  so 3+6+1=10
• 9 years agoHelpfull: Yes(2) No(1)
• sorry the answer given above by is wrong..mistakenly posted..please follow aakash jain answer...he is correct...
• 9 years agoHelpfull: Yes(1) No(1)
• how is AT=19 plz specify how!! it will be really helpful
• 9 years agoHelpfull: Yes(1) No(0)
• Answer is 10.
  Number the alphabets from 1 to 26.
  A=1, B=2,.....T=20.
  T-A=20-1=19
  19^2=361
  P-3, E-6, A-1
  Add on. 3+6+1=10
• 9 years agoHelpfull: Yes(1) No(0)
• Answer is:10
  
  (19)^2=361
  so, 3+6+1=10
• 9 years agoHelpfull: Yes(1) No(0)
• (AT)^2=A*T*A*T=P*E*A
  
  A*T*T=P*E
  
  1*4*4=8*2 =2*8
  
  so P=8 then p=2
  E=2 then p=8
  
  P+E=2+8=8+2=16
  
  A=1
  
  A+P+E=1+16=17
  
  
  
• 9 years agoHelpfull: Yes(0) No(9)
• 31*31=961(PEA).SO P+E+A=9+6+1=16..
• 9 years agoHelpfull: Yes(0) No(3)
• ANYONE PLEASE EXPLAIN IT CLEARLY;;;;;
  
  
• 9 years agoHelpfull: Yes(0) No(0)
• (19)^2 = 361
  P = 3 E=6 A=1
  ans = 10
• 9 years agoHelpfull: Yes(0) No(0)
• A=1,T=20
  (AT)^2=(120)^2=240
  PEA=240
  P+E+A=2+4+0=6
  Ans:6
• 9 years agoHelpfull: Yes(0) No(1)
• answer is 10..
  (A=1 & T=20 then T-A = 19)
  (AT)^2 = (19)^2 = 361 = PEA
• 9 years agoHelpfull: Yes(0) No(1)
• (11)^2=121 since (AT)^2=PEA, therefore P+A+E=4
• 9 years agoHelpfull: Yes(0) No(0)
• A value should be same integer so if we take 19 i.e A=1 AND T=9 THEN AT PEA ALSO A VALUE ALSO SHOULD BE 1 SO IF WE TAKE 19 THEN 19^2 WILL BE 361 AND SUM OF PEA IS 10
• 9 years agoHelpfull: Yes(0) No(0)
• a=1,t=20
  (120)^2=14400 so,.p+e+a=1+4+4=9
• 7 years agoHelpfull: Yes(0) No(0)