4 persons roll a dice. what is the probability that atleast two of them get the same number?

• =1-(PROBABILITY OF GETTING ALL DIFFERENT NOs)
  =1-( (6c1*5c1*4c1*3c1)/(6c1*6c1*6c1*6c1) )
  =1- (5/18)
  =13/18
• 9 years agoHelpfull: Yes(57) No(4)
• (6 * 1/6 * 1/6 * 5/6 * 4/6) + (6 * 1/6 * 1/6 * 1/6 * 5/6) + (6 * 1/6 * 1/6 * 5/6 * 1/6)=13/72
• 9 years agoHelpfull: Yes(4) No(3)
• 36/6^4 = 1/36
• 9 years agoHelpfull: Yes(3) No(1)
• probability of getting diff nos
  6*5*4*2=360
  tot probability=6^4=1296
  probability of getting diff nos
  360/1296=5/18
  probability of getting same no
  1-5/18=13/18
• 9 years agoHelpfull: Yes(3) No(2)
• total cases 6^4=1296
  unfavorable cases 6*5*4*3
  favorable cases where atleast 2 have same number =1296-360=936
• 9 years agoHelpfull: Yes(2) No(1)
• pls someone give the correct answer
  
• 9 years agoHelpfull: Yes(2) No(1)
• what is right answer can anyone explain?
  following is possible or not?
  (4c2*6 * 1/6^2 * 5/6 * 4/6) + (4c3*6 * 1/6^3 * 5/6) + (4c4*6 * 1/6^4)=47/72
  
  because when two have same no. may be (A,B),(B,C)---4c2 possible
  when three have same no. may be (A,B,C),(B,C,D)----4c3 possible
  when three have same no. (A,B,C,D)----1 possible
  
  and for all these dice value that is same may be 1 to 6
• 9 years agoHelpfull: Yes(1) No(0)
• All have got wrong answer
• 9 years agoHelpfull: Yes(1) No(2)
• Event=(2 get same,2 get diff),(3 get same,3 get diff),(4 get same)
  prob of getting same no=1/6
  prob of getting diff=5/6
  now,
  2 get same,2 get diff=1/6*1/6*5/6*4/6
  3 get same,3 get diff=1/6*1/6*1/6*5/6
  4 get same=1/6*1/6*1/6*1/6
  prob=(6*4!/2!*1/6*1/6*5/6*4/6)+(6*4!/3!*1/6*1/6*1/6*5/6)+(6*1/6*1/6*1/6*1/6)
  
• 9 years agoHelpfull: Yes(1) No(0)
• 4c2*1/6^2 +4c3*1/6^3 +4c4*1/6^4
• 9 years agoHelpfull: Yes(0) No(2)
• 43/108???
  2 get the same number= 1/6*1*5/6*4/6
  3 get same number=1/6*1*1*5/6
  4 get same number=1/6*1*1*1
  total= 43/108
• 9 years agoHelpfull: Yes(0) No(0)
• 6*(6*1*5*4)/6^4=5/9
• 9 years agoHelpfull: Yes(0) No(0)
• 13/18 is the right ans
• 9 years agoHelpfull: Yes(0) No(0)
• 1/36 is the correct answer
  
• 9 years agoHelpfull: Yes(0) No(0)
• The first person rolls a die, and gets a number.
  
  The second person has a 5/6 chance of rolling a different number.
  
  The third person has a 4/6 chance of rolling a number different from those two.
  
  The fourth person has a 3/6 chance of rolling a number different from all three.
  
  The odds that no two will roll the same number is 5/6*4/6*3/6 = 5/18 = .2777...
  
  That's the odds that no two will roll the same number, so the odds that two (or more) of them will roll the same number is 1-5/18 = 13/18 = .7222..
• 8 years agoHelpfull: Yes(0) No(0)