if 4 men role the same dice simultaneously, what is the probability that all of them get the same number on the dice. (please keep in mind the number of questions you solve this in the paper the lower cutoff in my college lowered than it always used to be, eoople who attempted16-18 are through and i haven't found yet among my mates anyone who have attempted more than 21 and is through)

• no. of events having all of them same no={(1111);(2222);(3333);(4444);(5555);(6666)}=6;
  total possibility=6^4
  prob.=6/6^4
  =>1/6^3
• 10 years agoHelpfull: Yes(38) No(2)
• 6/1296=1/216
• 10 years agoHelpfull: Yes(6) No(2)
• (1,1,1,1),(2,2,2,2,),(3,3,3,3,),(4,4,4,4),(5,5,5,5),(6,6,6,6)
  so there are 6 results so answer is
  6/1296=1/216.
• 10 years agoHelpfull: Yes(2) No(0)
• PROBABILITY =6/1296
• 10 years agoHelpfull: Yes(1) No(0)
• The probability is 6/6^4=1/6^3
• 10 years agoHelpfull: Yes(0) No(0)
• answer will be 6/2^4=1/216
  
• 10 years agoHelpfull: Yes(0) No(1)
• 1/216..
  6666
  5555
  4444
  3333
  2222
  1111
  
  that is 6 ways in which they are same ..
  6/6^4
• 10 years agoHelpfull: Yes(0) No(2)
• n(e)=6
  n(s)=6^4
  p=6/6^4=1/216
  
• 10 years agoHelpfull: Yes(0) No(0)
• no. of events having all of them same no. are={(1111),(2222),(3333),(4444),(5555),(6666)}=6
  Total no. of events = 6^4
  so ,probability that all of them get same no. of dice = 6/6^4 = 1/216;
• 10 years agoHelpfull: Yes(0) No(0)
• 6/6^4=1/6^3
• 10 years agoHelpfull: Yes(0) No(0)