what is the sum of 4+18+48+100+180+284+448+....up to 28terms

• 180670
  the series is " n[(n+1)^2] " in this pattern
  Case 1 put n=1
  u will get "4"
  Case 2 put n="2"
  u will get "18
  Case 3 put n="3"
  u will get "48"
  
  and so on
  put n=28 to get ans= 180670
• 10 years agoHelpfull: Yes(36) No(4)
• 180670
  the series is n[(n+1)^2]...apply the summation formula till n=28
  (n^2)[(n+1)^2]/4 + n(n+1)/2 + 2n(n+1)(2n+1)/6
  put n=28 to get ans= 180670
• 10 years agoHelpfull: Yes(11) No(1)
• sorry sum=180670
  
• 10 years agoHelpfull: Yes(4) No(2)
• ans:188384
  its n term is n(n+1)^2 =n^3+2n^2+n
  so sum upto n=28th term = (n(n+1)/2)^2 +2n(n+1)(2n+1)/6 +n(n+1)/2
  put n=28 u get sum=188384
• 10 years agoHelpfull: Yes(3) No(5)
• let n=28 n[(n+1)^2]=23548
  
• 10 years agoHelpfull: Yes(1) No(0)
• ans:23548
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• n(n+1)^2=28(29)^2=23548
• 8 years agoHelpfull: Yes(0) No(0)