In this question A^B means A raised to power B. Let f(X)=1+X+X^2+...X^6.
The remainder when f(X^7) is divided by f(X) is
a)0
b)7
c)6
d)none of the above

• take a example f(1)=1+1+1^2+1^3+1^4+1^5+1^6=1+1+1+1+1+1+1=7
  ans f(1^7)=f(1)=7
  so 7/7 then remainder is 0
  is it right
• 9 years agoHelpfull: Yes(11) No(11)
• 7 is the answer...
  use fermat little theorem
• 9 years agoHelpfull: Yes(4) No(1)
• 7 is the ans
• 9 years agoHelpfull: Yes(4) No(2)
• answer in open seesame is 7
• 9 years agoHelpfull: Yes(3) No(1)
• assume x=1 then remainder is 0.
  f(2)=1+2+4+8+16+32+64=127
  f(x^7)=1+(x^7)+(x^14)+(x^21)+......+(x^42)==>1+{(x^7)*[1+(x^2)+(x^3).....+x^6)]}
  ==>1+{(2^7)*[1+(2^2)+(2^3).....+(2^6)]==>1+16000=16001
  remainder is 26
  assume x=3 then remainder is something.
  so ans is none of the above.
  
• 9 years agoHelpfull: Yes(2) No(0)
• d) apply polynomial divison method
• 9 years agoHelpfull: Yes(1) No(0)
• please dont misguide others corrdct answer is 56 as once she selected one topping 7 toppings remain out of which she then selects one topping so 8c1 *7c1
• 9 years agoHelpfull: Yes(1) No(1)
• if we take x=2 we get different remainder than when x=1.
  hence answer is none of the above.
• 9 years agoHelpfull: Yes(1) No(0)
• remainder is 0
• 9 years agoHelpfull: Yes(0) No(2)
• plz explain
• 9 years agoHelpfull: Yes(0) No(4)
• .
• 9 years agoHelpfull: Yes(0) No(1)
• 0 is answer.....
• 9 years agoHelpfull: Yes(0) No(2)