There are 4 boxes colored red, yellow,
green and blue. If 2 boxes are selected, how
many combinations are there for at least one
green box or one red box to be selected?
A) 1 b) 6 c) 9 d) 5

• AnS:d
  Because My combination is (R,Y),(R,G),(R,B),(G,y),(G,B).So five combinations obtained.(5) ans
• 9 years agoHelpfull: Yes(14) No(1)
• Answer is 5
  since there are 3 possible ways to do
  first -> one box is red ,other boxes can be yellow and blue -> 2ways
  second -> one box is green, other boxes can be yellow and blue -> 2ways
  third -> both the boxes are red and green - 1way
  
  total - 2+2+1 =5 ways (since arrangement is not considered)
  
  hey sangam (G,G) & (R,R) is also a possibility but think if we selected one box i.e green or red then there are no remaining red or green boxes..
  
  So totally there are 4 boxes if u select 1 then remaining boxes will be 3..According to you there should be again 4 in order to select same box..which is not possible..
• 9 years agoHelpfull: Yes(3) No(0)
• can you tell me why we cant take (G,G)?
• 9 years agoHelpfull: Yes(2) No(6)
• f(f(n))=F(n)
  F(n)=o
  f(n)=2n+3
  f(2012)=2*2012+3
  =4027
  
• 9 years agoHelpfull: Yes(1) No(3)
• 5 combination bwhich are as follows
  (r,g)(r,b)(r,y)(g,y)(g,b)
• 9 years agoHelpfull: Yes(1) No(0)
• 1c1.2c1+1c1.2c1+2c2=2+2+1=5
• 9 years agoHelpfull: Yes(0) No(0)
• Pls send crct ans
• 9 years agoHelpfull: Yes(0) No(0)
• #sangam _ bcz there are singl box of each colr.so both same clrd box cnt b taken
  
• 9 years agoHelpfull: Yes(0) No(0)
• from the 4 boxes 2 boxes are selected as ry,rg,rb,gy,gb
  so ans is 5
• 9 years agoHelpfull: Yes(0) No(0)