F(n) is a function…where f(f(n))+f(n)=2n+3.F(n)=0;find f(2012) ?
A. 4123 B. 4027 C. 4131 D. 4321

• f(n)=0
  putting n=0
  f(0)=2n+3
  f(f(2012))+f(2012)
  =>f(0)=2n+3 where n=2012
  B.4027 ans....
• 9 years agoHelpfull: Yes(7) No(0)
• f(n)=0
  then putting n=0
  f(f(n))+f(n)=2n+3
  f(f(0))+f(0)=2n+3
  then put n=2012
  f(f(2012))+f(2012) so f(n)=0then also f(2012)=0
  2n+3
  2*2012+3=4027
  
  
• 9 years agoHelpfull: Yes(1) No(0)
• 4027 becouse it is given f(n)=0
  so f(f(n))=f(f(0))=f(0)=0
  hence f(f(n))+f(n)=2n+3
  f(n)=0 this means f(2012)=0
  0+0=2*2012+3=4027
• 9 years agoHelpfull: Yes(0) No(0)