How many different integers can be expresed as the sum of three distinct numbers from the set{13,10,23,28,33,36,43,48}?

• 55 is rt ans..bcoz 8c3-1=55. one is subtracted bcoz (43+13+10=66) and (33+23+10=66)..
• 9 years agoHelpfull: Yes(56) No(4)
• Permutations dont come here as order of three numbers isnt necessasry .my ans 8c3=56
• 9 years agoHelpfull: Yes(19) No(6)
• 8C3;here not mention that distinct sum,they told that only distinct number.
• 9 years agoHelpfull: Yes(4) No(2)
• permutations cannot be used since the orders matters therfore the ans is 8c3=56
• 9 years agoHelpfull: Yes(2) No(0)
• yogesh ahuja but how do u come to know that there are numbers whose sum is d same,ie 66??? I mean how can u do it faster? just keeping on adding wont mke sense na
• 9 years agoHelpfull: Yes(2) No(0)
• 8p3
  selecting 3 different numbers from 8 numbers
  
• 9 years agoHelpfull: Yes(1) No(6)
• 8 numbers can be arranged in 3 different integers so 8p3 so 8!/((8-3)!*3!) = 56
• 9 years agoHelpfull: Yes(1) No(2)
• i m getting confused...........what is right ans 55 or 56...
  
• 9 years agoHelpfull: Yes(1) No(0)
• they are saying different integer that means we cant count 66 two times
  thats why 55
• 9 years agoHelpfull: Yes(0) No(1)
• can u explain properly
• 9 years agoHelpfull: Yes(0) No(0)
• 13+10+23=46
  13+10+28=51
  13+10+33=56
  ......
  36+43+48=127
  46,51,56.....127
  Where difference is 5
  a=46,l=126
  (l-a)/d+1=(127-46)/5+1
  =16.2+1
  =17.2
• 4 years agoHelpfull: Yes(0) No(0)