In how many ways can we distibute 7 different objects to 3 different person so that either one or two does not get any object?
Plz explain me this problem

• 1st take that 2 of them doesn't get any of the objects...
  
  there are 3 persons so.....
  
  7 , 0 , 0 and this can be of 3 ways....like 0,7,0...0,0,7
  
  now one of the person doesn't get any object....
  it can be done by following way....
  
  6,1,0------3! ways
  5,2,0-------3! ways
  4,3,0--------3! ways..
  
  so total ways =3! + 3! + 3! +3 = 21 ways...
  
  
• 10 years agoHelpfull: Yes(76) No(17)
• here by prob we can say that if any 2 dont get any obj.total obj goes to 3rd person in 3 way.
  if 1 of them dont get object then 7 object goes to 2 person
  
  (1,6)=7c1
  
  (2,5)=7c2
  
  (3,4)=7c3
  
  (4,3)=7c4
  
  (5,2)=7c5
  
  (6,1)=7c6
  
  total 7c1+7c2+7c3+7c4+7c5+7c6=126
  
  for 2 person two way=2*126=378
  
  3rd person get the object in 3 way
  
  so tatal =3+378=381 way Ans
• 10 years agoHelpfull: Yes(34) No(22)
• here there are two cases , either or two wont get any object
  case:1
  two wont get object i.e,any of three can get all objects,therefore 3 ways.
  case2:
  seven must bedistributed among two it can distributed in 6 ways i.e (6,1) (1,6)
  (4,3) (3,4) (5,2) (2,5) besides any of three can be selected
  so total no of ways in second case is 3*6=18 ways
  adding both cases:- 3+18 = 21 ways
• 10 years agoHelpfull: Yes(7) No(5)
• 381 is the correct answer
• 10 years agoHelpfull: Yes(4) No(5)
• 7c3-(7c1+7c2)
• 10 years agoHelpfull: Yes(2) No(6)
• (3)^7-(2^7+1^7)=2058
• 10 years agoHelpfull: Yes(1) No(4)
• since it is possible that no object to one or two of them .we would have 3 choice for giving each object hence 3*3*3*3*3*3*3=2187
• 10 years agoHelpfull: Yes(1) No(3)
• Formula is :- Combination of n object taken r at a time when k object never chosen
  (n-k)C(r)
  
  so there are two cases for 1 and for 2
  thus (6)C(3)+(5)C(3)=30
• 10 years agoHelpfull: Yes(1) No(2)
• if 1 and 2 doesnt get any object then the 3rd person will get that in3 ways -
  007,700,070.
  one one of the person will not get any object
  if 1st person doesnt get the object-
  0,6,1 or 0,1,6
  0,4,3 or 0,3,4
  0,2,5 or 0,5,2
  3!*6=36
  accordingly for 2nd and 3rd person
  36 and 36
  so the total no of way is
  3*36+3= 108+3 =111
• 10 years agoHelpfull: Yes(0) No(3)
• 147
  3c1*7c2 + 3c2*7c1
  
• 10 years agoHelpfull: Yes(0) No(2)