jack is faster than paul and jack and paul each walk 24 km. sum of their speed is 7km/h and sum of time taken by them is 14 hours. then jack speed is equals to:

• since distance=24 km
  let jake speed=x kmph
  paul speed=y kmph
  a/c to question
  x+y=7
  or
  y=7-x
  now,
  24/x+24/y=14
  or 24/x+24/7-x=14
  or
  1/x+1/7-x=14/24=7/12
  x+7-x/7x-x*x=7/12
  by solving
  x=3,4
  or
  y=4,3
  by using option
  4km/h
• 10 years agoHelpfull: Yes(30) No(0)
• ans is 4km/hour
  let jack's speed x
  24/x + 24/(7-x)=14
  => x=4 or x=3
  as jack is faster. ans id 4km/hr
• 10 years agoHelpfull: Yes(11) No(0)
• let speed of j & p is x & y than
  a/c to Q sum ofspeed x+y=7
  sum of time 24/x + 24/y =14 after both eq. x=4 & y=3
  
  
• 10 years agoHelpfull: Yes(0) No(0)
• 4 km/hr
  4+3=7
  4*3=12
  and jack speed>paul speed
• 10 years agoHelpfull: Yes(0) No(0)