18 sharpeners are bought for 100 rupees. White coloured sharpener is 1 rupee more than brown color. What are number of white sharpeners and what is price for per sharpener?

• let x be the no. of white sharpeners
  and y be the no of brown sharpeners
  and let cost of 1 brown sharpener be a
  
  then we have
  x+y=18
  and
  (a+1)*x +a*y=100
  solving
  x=100-18*a
  hence we get ,
  a=5 , x=10 (as x cannot be in fraction)
  and y=8
  cost of white sharpener =5+1 =6
• 9 years agoHelpfull: Yes(15) No(0)
• 10 white sherperners each of 6 rupees;
  let der be 'a' white sharperners and 'b' brown
  and let each white one be 'x' and brown 'y'
  then ax+by=100(I); a+b=18(II); x-y=1(III);
  solving (I) and (II) a=100-18y;
  a must be integer less than 18;y must be an integer
  a=10 for y=5;
  therefore x=6 and b=8;
• 9 years agoHelpfull: Yes(3) No(0)
• brown sharpner=8*5=40
  white sharpner=10*6=60
  total 100
• 9 years agoHelpfull: Yes(2) No(0)
• told that white is one more than brown so w=b+1. if white is brought is brought for rs and total count is 10 total cost spend for white alone is 6(price)*10(quantity)=60. remaining 8 brown will surely one less than white so it cost rs and remaining sharpener that is 5(cost)*8(quantity)=40. 40+60=100 and 10+8=18, ans: 10 sharpener and 6rs/sharpner
• 9 years agoHelpfull: Yes(2) No(0)
• total 10 white sharpeners and each Rs 6
• 9 years agoHelpfull: Yes(1) No(3)
• 18 sharpener 100 rs
  white + 1 = brown
  let white = 4 and brown = 5 (this assumption is done by trail and error)
  now 4 * 5 white sharpeners = 20 rs and 16 * 5 = 80 rs therefore from given problem no. of white sharpeners = 5 and price of each sharpener is 4 rs
• 9 years agoHelpfull: Yes(0) No(4)
• sorry interchange white and brown and if option are given we could solve more easily
• 9 years agoHelpfull: Yes(0) No(1)
• no of white sharpeners=10.
  and cost rupees 6.......
  so total=10*6=60 rs.
  rest no of brown sharpeners=18-10=8.
  this cost rs 5 per sharpeners....
  
  we can solve it through hit and trial method
• 9 years agoHelpfull: Yes(0) No(0)