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Numerical Ability
Probability
The probability of occurrence of two events E and F are 0.25 and 0.30 respectively. The probability of their simultaneous occurrence is 0.14. The probability that either E occurs or F occurs is
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- Ans:.41
p(E U F) = p(E) + P(F) - p(E ^ F)
=.25+.30 -.14 =.41 - 10 years agoHelpfull: Yes(24) No(0)
- i guessed answer is 0.41
- 10 years agoHelpfull: Yes(5) No(0)
- the probablity of either E occurs or F occurs=P(E)*P(F') + P(F')*P(E)
=0.25*0.70 + 0.75*0.30
=0.40
so probality of occurence of either events will be 0.40 - 10 years agoHelpfull: Yes(4) No(0)
- p(e)+p(f)-p(e&f)=>
0.25+0.30-0.14=0.41 - 10 years agoHelpfull: Yes(3) No(0)
- It's 0.40 ... (i.e) 0.25*0.70 + (0.30*0.75)
If u follow (EuF) rule that gives probability of occurance of both E and F - 10 years agoHelpfull: Yes(2) No(0)
- .40 rght ans
- 10 years agoHelpfull: Yes(1) No(1)
- p(EUF)=p(E)+p(f)-p(E^F)
0.14=0.25+0.30-P(E^F)
P(E^F)=0.41 - 10 years agoHelpfull: Yes(1) No(0)
- P(E U F)=0.41
- 10 years agoHelpfull: Yes(0) No(0)
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