TCS
Company
Numerical Ability
Time Distance and Speed
Jack and Paul covers 10 km. Jack has speed 1.5 km/h more than Paul and reaches the destination 1.5 Min before Paul. So what is the speed of Jack.
Read Solution (Total 14)
-
- let speed of paul =x kmph
speed of jack=(x+1.5) kmph
(10/x)-(10/x+1.5)=(1.5/60) hr
solving we get
x=23.75 kmph
jack speed should be=25.25 kmph - 10 years agoHelpfull: Yes(33) No(1)
- Let speed of paul =x kmph
then speed of jack=x+1.5
now the equation becomes
(10/x)-(10/x+1.5)=1.5 min
solving the equation we get
x^2+1.5x-10=0
x=2.5 and -4
so paul speed=2.5kmph
then Jack Speed=4kmph - 10 years agoHelpfull: Yes(23) No(17)
- statement wrong it should be 1.5 hours
then
10/x-10/(x+1.5)=1.5
we get x=2.5
and jack speed is 4 - 10 years agoHelpfull: Yes(7) No(3)
- let speed of paul=x
then speed of jack=x+1.5
now the equation becomes-
(10/x)-(10/x+1.5)=1.5
solving the equation u get
x^2+1.5x-10=0
now in TCS paper options were given-
a)2
b)4
c)8
d)6
by hit and trial subtract 1.5 from all the above and put in the above equation to get result.
- 10 years agoHelpfull: Yes(5) No(2)
- let speed of paul =x kmph
speed of jack=(x+1.5) kmph
(10/x)-(10/x+1.5)=(1.5/60)
solving above equ.
we get
x=23.75 kmph
paul speed = 23.75
jack speed should be=25.25 kmph - 10 years agoHelpfull: Yes(3) No(0)
- j=1.5 m/h let time taken by jack(x-1.5/60)
----------------------------
p let speed s 10 km Let paul take x h to reach
for paul from formula speed=d/t
1.5=10/(x-1.5/60)
we get x=803/120
for paul s=10/x=10*120/803 simply putting value of x
s=1.494 (ANSWER) ie paul speed less than jack - 10 years agoHelpfull: Yes(2) No(9)
- I think it's 25.25kmph
- 10 years agoHelpfull: Yes(2) No(8)
- sorry for the wrong answer. the equation i m getting is:
p^2 +1.5p -600=0
where p=pauls speed
and jake speed is j=1.5+p - 10 years agoHelpfull: Yes(2) No(3)
- Let speed of Paul=x km/hr
then
speed of jack=(x+1.5)km/hr
So a/q
(10/x)-(10/(x+1.5))=(1.5/60)
solve for x
we get x=23.75 and x=-25.25(not possible)
so speed of jack is 23.75+1.5=25.25 km/hr - 10 years agoHelpfull: Yes(1) No(0)
- I THINK JACK SPEED IS 4 AND PAUL SPEED IS 2.5
- 10 years agoHelpfull: Yes(0) No(8)
- i am getting Jacks speed as 200 kmph.
- 10 years agoHelpfull: Yes(0) No(6)
- ANS=10KM/Hr
- 10 years agoHelpfull: Yes(0) No(1)
- the answer is 4
- 10 years agoHelpfull: Yes(0) No(1)
- If YOU CONVERT 1.5 MINUTE IN HOUR THEN ANSWER WILL BE 22.5 OTHERWISE 4
- 10 years agoHelpfull: Yes(0) No(1)
TCS Other Question