1223334444112222333333444444441112222223333333334……………………………………what is 2888th no in this sequence

• Ans is:3
  1223334444........
  First term=1+2+3+4=10
  Second term=2+4+6+8=20
  It increase in double 10,20,30,40,60..
  In 23rd term sum of total is=2760
  2888-2760==128
  24th term 1 will cme 24 times,2 will cme 48 times,3 will cme 72 times..
  24+48+72=144
  So 144 is>128
  Ans is:3
  
• 9 years agoHelpfull: Yes(26) No(2)
• ans is: 3. there are 1 1s 2 2s 3 3s 4 4s . and for the next series it is multiplied by 3 of its numbers and so on.
• 9 years agoHelpfull: Yes(4) No(0)
• 1 to 4 as a set it repeats in order 10,20,30,...... so 23 full sets sums up to 2760 so now in 24th set 1's and 2's sums to 72 and next 72 will be 3's so i guess 3 will be 2888th number
• 9 years agoHelpfull: Yes(3) No(0)
• ANS is 3...
• 9 years agoHelpfull: Yes(1) No(1)
• Sorry the answer will be 3 only...
• 9 years agoHelpfull: Yes(1) No(0)
• Here it form GP with C.R=2
  
  therefore : 1(2^n-1)/(2-1) + 2(2^n-1)/(2-1) + 3(2^n-1)/(2-1) +4(2^n-1)/(2-1) = (2^n-1)10
  
  for n=8
  (2^8-1)*10=2560
  2888-2560=328.
  
  now the series starts with 9 1's,10 2's,11 3'3 and so on...
  
  hence 2888th term will be 2.
  
  Answer is 2
  
• 9 years agoHelpfull: Yes(0) No(4)
• 1,2,3,4 then 2,4,6,8 and continues......answer will be 1 at 2888th term
• 9 years agoHelpfull: Yes(0) No(1)
• ans is 3.firstcount digits upto 4 total are 10 next 20....
  so using n(n+1)/2*10
• 9 years agoHelpfull: Yes(0) No(0)
• first term has 1 1's 2 2's 3 3's and 4 4's total nos wil be 10
  second terms has 2 1's 4 2's 6 3's and 8 4's total nos wil be 20
  it goes in such a way like 10+20+40+80+160+320+640+1280=2550 2888-2550=338
  remaining there will be 338 digits nineth term has 2^9 1s so ans will be 2
• 9 years agoHelpfull: Yes(0) No(1)
• ans. is 3 but they are not becoming twice
  2 is becoming twice ,3 is becoming thrice so
  after 23rd
  1 is 23 times=23
  2 is 2*23times=46
  3 is 3*23times=69
  
  
• 9 years agoHelpfull: Yes(0) No(0)