When the number is written in base b we have 12 25 333 The value of b is

ans-7
12*25=333
(1*b^1+2*b^0)* (2*b^1+5*b^0)=(3*b^2+3*b^2+3*b^0)
(b+2)(2b+5)=3b^2+3b+3
2b^2+5b+4b+13b^2+3b+3
b^2-6b-7=0
b=7,-1
base can't be negative so ans is 7
10 years agoHelpfull: Yes(11) No(0)
Ans is:7
Take option to solve it is best way..
Condition is LHS==RHS
12*25..
1*7+2=9
2*7+5=19
9*19=171
Now 333
3*7^2+7*3+3=171
So LHS==RHS
10 years agoHelpfull: Yes(6) No(1)
convert all the num to base x
(1*x+2*x^0)*(2*x+5*x^0)=(3*x^0+3*x^1+3*x^2)
solving X=7
10 years agoHelpfull: Yes(2) No(0)
R u sure this is the actual question?
It's coming out -1 and base can't be in negative. I think smthng is missing
10 years agoHelpfull: Yes(1) No(3)
Let the base = b
So, (b+2)(2b+5) = (b+2)(2b+5)=3b2+3b+3
2b2+9b+10=3b2+3b+3
b2−6b−7=0
Solving we get b = 7 or -1
So b = 7
10 years agoHelpfull: Yes(1) No(0)
12*25=333
(1*b^1+2*b^0)*(2*b^1+5*b^0)=(3*b^2+3*b^1+3*b^0)
(b+2)*(2b+5)=(3b^2+3b+3)
b^2-6b-7=0
b=7
10 years agoHelpfull: Yes(0) No(0)
value of b is 7
(b+2)*(2b+5)=3b^2+3b+3
by solving the above equation we get ans as 7
10 years agoHelpfull: Yes(0) No(0)

When the number is written in base b, we have 12*25 =333. The
value of b is ?