in the question A^B means A raised to the power B,f(x)=ax^4-bx^2+x+5,f(-3)=2,then f(3)=?

• Ans is:8
  f(-3)=2
  2=a(-3)^4-b(-3)^2-3+5
  2=81a-9b+2
  81a-9b--->1
  Then f(3)
  81a-9b=81a-9b+3+5-->2
  Solve the eq..we can get 8.....
• 10 years agoHelpfull: Yes(33) No(5)
• ans:8
  f(-3)=81a-9b+2=2
  so that 9a-b=0
  f(3)=81a-9b+3+5
  =9(9a-b)+8
  =9(0)+8
  =8
• 10 years agoHelpfull: Yes(22) No(0)
• The solution can be done in
  f(0)=5
  f(-3)=2
  for increment of x value by 3 the functional value also increased by 3
  so, f(3)=5+3=8
• 10 years agoHelpfull: Yes(5) No(0)
• Sorry the answer is 8 as said by karthikeyank
• 10 years agoHelpfull: Yes(2) No(0)
• f(-3)=81a-9b+2
  f(-3)=2
  --->81a-9b=0
  so f(3)=81a-9b+8=0+8
  f(3)=8
  
• 10 years agoHelpfull: Yes(1) No(0)
• 1st 2 term eliminate so 3+5=8;
• 10 years agoHelpfull: Yes(1) No(1)
• -4 is the solution
  
• 10 years agoHelpfull: Yes(0) No(3)
• 2 is the answer
• 10 years agoHelpfull: Yes(0) No(2)
• ans:8
  f(-3)=a(-3)^4-b(-3)^2+-3+5=2
  81a-9b=0 let it be euation (1)
  now f(3)=a(3)^4-b(3)^2+3+5=0
  81a-9b-8=0 let be eguation (2)
  now subtitue value of euation (1) in euation(2)
  than it will be 81a-9b=8
• 10 years agoHelpfull: Yes(0) No(0)
• f(-3)=81a-9b+2
  
  2=81a-9b+2
  
  so b=9a
  
  put it in f(3)=81a-9b+8
  
  f(3)=8
  
• 10 years agoHelpfull: Yes(0) No(0)
• f(x)=ax^4-bx^2+x+5
  =>f(-3)=a(-3)^4-b(-3)^2+(-3)+5=2
  =>f(-3)=a(3)^4-b(3)^2=0--(eqn1)
  hence
  f(3)=a(3)^4-b(3)^2+3+5(by eqn1)
  f(3)=8
• 10 years agoHelpfull: Yes(0) No(0)
• f(-3)=81a-9b-3+5
  or,2=81a-9b+2
  or,81a-9b=0
  so, f(3)=81a-9b+3+5
  f(3)=8
• 10 years agoHelpfull: Yes(0) No(0)
• 2= a81-9b-3+5
  so b=9a,
  again,
  f(3)= 81a-9b+3+5
  put the value of b=9a and we get
  f(3)=81-9*a +3+5= 8
  ans 8
• 10 years agoHelpfull: Yes(0) No(0)
• Ans is:8
  f(-3)=2
  2=a(-3)^4-b(-3)^2-3+5
  2=81a-9b+2
  81a-9b--->1
  Then f(3)
  81a-9b=81a-9b+3+5-->2
  Solve the eq..we can get 8.....
  Read more at http://www.m4maths.com/39393-in-the-question-A-B-means-A-raised-to-the-power-B-f-x-ax-4-bx-2-x-5-f.html#eTUro7yF9qduvRvo.99
• 9 years agoHelpfull: Yes(0) No(0)
• here ans will be 8
  
• 9 years agoHelpfull: Yes(0) No(0)
• 8 iscorrct ans
• 9 years agoHelpfull: Yes(0) No(0)
• f(-3) = a(-3)4 - b(-3)2 + (-3) + 5 = 81a - 9b + 2 = 2 So 81a - 9b = 0
  f(3) = a(3)4 - b(3)2 + (3) + 5 = 81a - 9b + 8
  Substituting the value of 81a - 9b = 0 in the above we get f(3) = 8
• 7 years agoHelpfull: Yes(0) No(0)
• Ans is:8
  f(x)=ax^4+bx^2+x+5
  f(-3)=a(-3)^4+b(-3)^2-3+5
  2=a(3)^4+b(3)^2-3+5
  2+3=a(3)^4+b(3)^2+5
  5=a(3)^4+b(3)^2+5 ----->1
  f(3)=a(3)^4+b(3)^2+3+5
  form eq 1
  f(3)=5+3
  f(3)=8
• 5 years agoHelpfull: Yes(0) No(0)