how many ways does 10 pencils given to four children such that each get atleast 1?

• Ans is:84
  (10-1)C(4-1)=9C3=9*8*7/3*2=504/6=84
• 9 years agoHelpfull: Yes(44) No(4)
• There are 10 pencils
  so 1 given to each
  hence 6 remains
  as per product rule and sum rule the total ways will be
  4*(6+5+4+3+2+1)=84
• 9 years agoHelpfull: Yes(14) No(1)
• Formula is (n-1)C(r-1)
• 9 years agoHelpfull: Yes(12) No(3)
• Number of ways of distributing n identical things among r person where Each person get atleast one...
• 9 years agoHelpfull: Yes(8) No(1)
• in which case we use this formula..? only when we have to distribute atleast one to all ?
• 9 years agoHelpfull: Yes(1) No(1)
• @karthikeyank plz explain
• 9 years agoHelpfull: Yes(1) No(0)
• (10-1)C(4-1)
• 9 years agoHelpfull: Yes(1) No(1)
• pencils are same and 1 children get 1 pencil
  remaining pencils are 6
  so
  1c=6pcncils
  2c=6pencils
  3c=6pencils
  4c=6pencils
  answer is 6^4=1296
• 9 years agoHelpfull: Yes(1) No(8)
• 4^10
  1 pencil can be given to 4 children in 4 ways.
  similary 10 pencils in 4^10
• 9 years agoHelpfull: Yes(1) No(3)
• (10-1)C(4-1)=84
• 9 years agoHelpfull: Yes(1) No(0)
• @karthikey- plz explain the solution, and how to use this formula
• 9 years agoHelpfull: Yes(0) No(0)
• @Karthik
  plz explain the answer
• 9 years agoHelpfull: Yes(0) No(1)
• i think ans is 10C4
• 9 years agoHelpfull: Yes(0) No(7)
• note:if pencil are similar.
  first give 1 pencil to each children.
  now as 6 pencil are remaining.
  now 1st pencil out of 6 can be given to any 4 children i.e. there are four ways to give 1 pencil to 4 children.
  -->similarly, 2nd pencil can be given to any of 4 children.. and so on..upto 6th pencil.
  thus we get 4^6 ways .
  which is 4^6=256.
  
• 9 years agoHelpfull: Yes(0) No(5)
• (n-1)C(r-1)
  Its a concept we use when u have to distribute n similar item between r persons such that all get at least 1. So. 9C3
• 9 years agoHelpfull: Yes(0) No(0)
• can any one say without using formulae?????
• 9 years agoHelpfull: Yes(0) No(0)
• number of ways distributing n identical things among p groups so that atleast each get one = (n-1)c(p-1)
  so ways= 9c3
• 9 years agoHelpfull: Yes(0) No(0)
• (10-1)C(4-1)=9C3=84
• 9 years agoHelpfull: Yes(0) No(0)
• distribution of n things in n numbers hat every one get atleast one item =
  (n-1)C(r-1)
  so we get (10-1)C(4-1)=84
• 9 years agoHelpfull: Yes(0) No(0)
• if we give 1 pencil to four children ... after that 6 pencils are remaining .... thus .. we can ditribute .. these in ..= 6*6*6*6=256 ways..
• 9 years agoHelpfull: Yes(0) No(0)
• 10c4-4c2/10c4
  
• 9 years agoHelpfull: Yes(0) No(0)
• plz explain clearly
  
• 9 years agoHelpfull: Yes(0) No(0)
• (10-1)C(4-1)=84
• 9 years agoHelpfull: Yes(0) No(0)
• (n-1)C =9C3
  (r-1)
• 9 years agoHelpfull: Yes(0) No(0)