Two consecutive numbers are removed from progression 1,2,3,4,......n.The arithmetic mean of remaining numbers is 26 1/4.The value of n is

• any two consecutive numbers you eliminate,but the average always must be in the range from (n+1/2)+1 to (n+1/2)-1
  here the average after removing consecutive nos is 26.25
  now we have to check options.say the option is given 50.
  then,average of (1+2+....+50)50=51/2=25.5
  it covers the range 24.5 to 26.5
  so 26.25 belongs to that range.so ans=50
• 10 years agoHelpfull: Yes(22) No(3)
• n(n+1)/2-n/2-n/2 +1 = 26.25(n) -52.5 solving this u will get n=50
• 10 years agoHelpfull: Yes(9) No(1)
• answer may be 136
• 10 years agoHelpfull: Yes(0) No(7)
• 1+2+3+.............+23=286
  Hence ans is 23
• 10 years agoHelpfull: Yes(0) No(4)
• answer is n=54
  becoz
  26.25*52=1365
  1+2+3.........+54=1431
  and 1+2+3...............+53=1378
  condition satisified in 54 ans
• 10 years agoHelpfull: Yes(0) No(4)
• n(n+1)/2=26.5
  n(n+1)=53
  n2+n=53
  n^2+n-53=0
  n^
  n
• 10 years agoHelpfull: Yes(0) No(2)
• wt's d crct ans?
  
• 10 years agoHelpfull: Yes(0) No(1)
• can u explain little more saynee
• 10 years agoHelpfull: Yes(0) No(1)
• if something missing digit is x,y
  so avg. of this no. is x+y/2
  airthmtic mean of 1,2 ,3,4.......n
  n(n+1)/2n-x+y/2=52.5/2
  (n+1)/2-x+y/2=52.5/2 53/2-.5/2
  (n+1)/2=53/2 n=52
• 10 years agoHelpfull: Yes(0) No(0)
• i dont get it
• 10 years agoHelpfull: Yes(0) No(0)
• average (n(n+1)/2)/n=109/4
  n=53.5 or 54
  
• 10 years agoHelpfull: Yes(0) No(0)