The price of a commodity(in rupees per kilogram) is 100 + 0.1n, on the nth day of 2007 (n = 1, 2,….., 100), and then remains constant. On the other hand, the price of another commodity (in rupees per kilogram) is 89 + 0.15n, on the nth day of 2007 (n=1,2, …, 365). On which date in 2007, will the price of these two commodities be equal?

a. May 21
b. April 11
c. May 20
d. April 10

• 20 may
  100 + 0.1*100 =110
  110 = 89 + 0.15n
  solving this
  n = 140 days
  which is 20th of may
  
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• Total days = 140
  Now this is which date...... To find out........
  From jan to may 31...... Total days 151..... And 151-140=11.......So 31st may - 11 days =20th may (ans)
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• may 21, total days=140,
  cost =rs 110
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• 100+.10 after 100 days 100+10=110 89+.15*100=104 89+.15n=110 so ans is 20 may
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• 110 = 89.15 + (n-1)*(0.15)
  20.95 = (n-1)*(0.15)
  by solving
  n = 140.33
  thus we should take 141th day and that is May 21
  ans= May 21
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• may 20 is the ans
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• ques ki language kayde se likha kro kam se kam...
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• 20th May is the answer
• 10 years agoHelpfull: Yes(0) No(1)
• 100 + 0.1*100 =110
  110 = 89 + 0.15n
  solving this
  n = 140 days
  so it is May 20 of 2007
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