A rectangular box has six surfaces. The area of its front is 54 square inches; the area of its side is 72 square inches; and the area of its top is 108 square inches. What is the volume of the box?

• l*b=108
  b*h=72
  l*h=54
  Solving
  l=9
  h=6
  b=12
  Volume=l*b*h=9*6*12=648
• 9 years agoHelpfull: Yes(22) No(2)
• let l,b,h be dimention of rectangular box
  ;
  lb=54
  bh=72
  hl=108
  => l^2*b^2*h^2=108*72*108
  => lbh=648
• 9 years agoHelpfull: Yes(5) No(1)
• we have h*b=108,L*b=54 & L*h=72. Multiplying these eqn we have L^2*b^2*h^2=108*54*72.Taking square root both the sides we have volume= 648cubic inches
• 9 years agoHelpfull: Yes(2) No(1)
• 2*(54+72+108)=468
• 9 years agoHelpfull: Yes(0) No(5)
• 864
  l*b=54=9*6
  b*h=72=12*6
  h*l=108=12*9
• 9 years agoHelpfull: Yes(0) No(1)
• answere = 648 (lbh) ,as h*l=72 ,h*b=108, l*b=54 solve three equations to get l,h,b .
• 9 years agoHelpfull: Yes(0) No(1)
• w*h=54; w*l=108; l*h=72;
  w=108/l; w*h=54; 108/l*h=54; => 2h=l;
  lh=72; 2h*h=72=> h=6
  l=12; w=9;
  v=6*12*9=648
  
• 9 years agoHelpfull: Yes(0) No(1)
• lb=54
  bh=72
  hl=108
  Solving
  l=9
  h=6
  b=12
  Volume=l*b*h=9*6*12=648
  
• 9 years agoHelpfull: Yes(0) No(1)
• given lb=108, lh=72,bh=54
  lh*lb*bh=108*72*54
  l^2*b^2*h^2 =419904
  taking sq root
  vol=l*b*h=648
• 9 years agoHelpfull: Yes(0) No(1)
• answer 12*9*6=648
• 9 years agoHelpfull: Yes(0) No(1)