A rectangular box has six surfaces The area of its front is 54 square inches the area of its side

let l,b,h be dimention of rectangular box
;
lb=54
bh=72
hl=108
=> l^2*b^2*h^2=108*72*108
=> lbh=648
10 years agoHelpfull: Yes(5) No(1)
we have h*b=108,L*b=54 & L*h=72. Multiplying these eqn we have L^2*b^2*h^2=108*54*72.Taking square root both the sides we have volume= 648cubic inches
10 years agoHelpfull: Yes(2) No(1)
2*(54+72+108)=468
10 years agoHelpfull: Yes(0) No(5)
864
l*b=54=9*6
b*h=72=12*6
h*l=108=12*9
10 years agoHelpfull: Yes(0) No(1)
answere = 648 (lbh) ,as h*l=72 ,h*b=108, l*b=54 solve three equations to get l,h,b .
10 years agoHelpfull: Yes(0) No(1)
w*h=54; w*l=108; l*h=72;
w=108/l; w*h=54; 108/l*h=54; => 2h=l;
lh=72; 2h*h=72=> h=6
l=12; w=9;
v=6*12*9=648
10 years agoHelpfull: Yes(0) No(1)
lb=54
bh=72
hl=108
Solving
l=9
h=6
b=12
Volume=l*b*h=9*6*12=648
10 years agoHelpfull: Yes(0) No(1)
given lb=108, lh=72,bh=54
lh*lb*bh=108*72*54
l^2*b^2*h^2 =419904
taking sq root
vol=l*b*h=648
10 years agoHelpfull: Yes(0) No(1)
answer 12*9*6=648
10 years agoHelpfull: Yes(0) No(1)

A rectangular box has six surfaces. The area of its front is 54 square inches; the area of its side is 72 square inches; and the area of its top is 108 square inches. What is the volume of the box?