among 200 employees, 100 employees play cricket, while 125 employees do not play hockey. 50 employees play both Cricket and Hockey. How many employees play at least one game?

• employees play hockey= 200-125= 75
  employees play cricket = 100
  play both= 50
  
  then P(AUB) = P(A)+P(B)-P(A intersection B) = 100+75-50 = 125
• 10 years agoHelpfull: Yes(30) No(1)
• CuH=100+(200-125)-50=125
• 10 years agoHelpfull: Yes(2) No(0)
• P(K)+P(H)-P(K&H)=P(K U H)=125
• 10 years agoHelpfull: Yes(1) No(0)
• cricket:C=100
  hockey:H=200-125=75
  C and h both=50
  atleast one game=CUH=100+75-50=125
• 7 years agoHelpfull: Yes(1) No(0)
• p(aUb)=p(a)+p(b)-p(a intersection b)
  =100+(200-125)-50
  125
• 10 years agoHelpfull: Yes(0) No(0)
• employees play hockey=200-125=75
  so,P(CUH)=P(C)+P(H)+P(CnH)=100+75-50=125
• 10 years agoHelpfull: Yes(0) No(0)
• consider A=100(employee play cricket) B=200-125(employee play hockey)=75 given A∩B=50
  therefore A∪B=A + B - A∩B=100 + 75 - 50 = 125
• 8 years agoHelpfull: Yes(0) No(0)