A person brought two clocks. the cost price of one of them exceeds the cost of the other by 1/4th. he sold the dearer one at a gain of 10% an the other at a gain of 7.5% and thus got rs 98 in all as S.P. Find the cost Price of the cheaper one.

• let CP of a be x and other than become 5x/4
  So SP Of b is 5x/4 + x/8 = 11x/8
  and SP of a is x + 3x/40 =43x/40
  11x/8 + 43x/40 = 98
  Thus x comes 40 ans
• 9 years agoHelpfull: Yes(20) No(2)
• let the cp of cheaper one is x then cp of second is x+x*1/4=5x/4
  110*5x/*100+107.5*x/100=98
  1.375x+1.075x=98
  x=98/2.45
  x=40
  so cost price of cheaper one is Rs 40
• 9 years agoHelpfull: Yes(13) No(1)
• let cp of one clock be x
  therefore cp of 2nd clock=5x/4
  profit of dearer clock=(10*5x)/(100*4)=x/8
  profit of cheaper clock=(7.5*x)/100=3x/40
  total profit= 3x/40+x/8 = x/5
  total cp= x+5x/4 = 9x/4
  SP=CP+PROFIT
  98=9x/4+x/5
  x=40 ans
• 9 years agoHelpfull: Yes(6) No(0)
• let cp one clock is x then another x+1/4x=5x/4
  therefor x,5x/4
  10%of x+7.5%5x/4=98
  1/10(x)+9.3x=98
  9.4x=98
  x=10
• 9 years agoHelpfull: Yes(4) No(5)
• let of cp of 1st clock is x,then cp of another clock will be 5x/4
  now,sp of 1st clock=x+x*7.5/100=43x/40
  sp of 2nd clock=5x/4 + 5x/4*10/100=55x/40
  43x/40 + 55x/40=98
  x=40
  cost price of cheaper will be 40
• 9 years agoHelpfull: Yes(3) No(0)
• sorry friends i have taken 10% it is 110% and 107.5%
  therefore 110/100=1.1
  107.5/100=1.075
  by taking we get x=40.4
  1.1*40.4=44
  and another 54 so cheaper one is 44
  
• 9 years agoHelpfull: Yes(2) No(4)
• if S.P means Sales Profit then ans is 490.
  if S.P means Sales Price then ans is 40.
• 9 years agoHelpfull: Yes(2) No(0)
• Let the 2 C.p's be x & 1.25 x
  and the 2 profit %ages are 7.5 & 10
  so Sp will be (1.25x)10 + (x)(1.075)=98
  i.e 98000=2450x or x=40
• 9 years agoHelpfull: Yes(2) No(0)
• let the cost price of cheaper one is x,then cost price of costly item is 5x/4
  nw,he sells the dearest one(means the one having high price) at 10%profit and other(low price) at 7.5% profit...so s.p of costly item=5x/4+x/8 and s.p of low cost item is x+3x/40
  now total s.p=5x/4+x/8+x+3x/40=98x/40
  it is given that total s.p=98...so 98x/40=98
  so x=40
• 9 years agoHelpfull: Yes(2) No(0)
• ans is 490 rs
  let a,b are two clockes
  let x is cost of A, the cost of B is x+x/4=5x/4.
  i.e (x*7.5/100)+((5x/4*10)/100)=98.
  30x+50x=98*100*4
  80x=39200
  x=39200/80
  x=490
  
  
• 9 years agoHelpfull: Yes(1) No(3)
• Let the CP be 100 and 125,
  Then SPs become 110 and 134
  Total SP given in prob. is 98.
  
  110+134=244
  
  98/244 X 110 (cheaper one) = 44 This is SP.
  
  CP= SP X 0.9091 = 40
  
  Ans is 40
• 9 years agoHelpfull: Yes(1) No(0)
• ans 490
  let c.p of cheaper product is x
  so c.p of dearer one is (x+X/4)= 5x/4
  10% of 5x/4 + 7.5% of x = 98
  x= 490
• 9 years agoHelpfull: Yes(0) No(3)