the shopkeeper charged 12 rupees for a bunch of chocolate. but i bargained to shopkeeper and got two extra ones, and that made them cost one rupee for dozen less then first asking price .

how many chocolates i recieved in 12 rupees ??
a)10
b)16
c)14
d)18

• let no. of chocolates=x=x/12dozen
  price of x/12 dozen is rs 12
  so price of 1 dozen is 144/x
  2nd condition
  144/(x+2) +1=144/x
  go through option x=16
• 9 years agoHelpfull: Yes(46) No(14)
• D.18 chocolets, then cost of each chocolate is 12/18=0.6666 then cost of dozen(12) chocolates is 0.6666*12=8
  
  at first 18-2=16 chocolates then cost of each is 12/16=0.75 then cost of 12 chocolates is 12*0.75=9
  9-8=1
  so answer is 18 chocolates
• 9 years agoHelpfull: Yes(21) No(22)
• 12/x - 12/(x+2)= 1/12
  on solviing x=16.....
• 9 years agoHelpfull: Yes(15) No(6)
• case 1:no. of chocolate =x
  total cost=12
  cost of one dozen chocolate(C1)=(12/x)*12=144/x
  
  case 2:no. of chocolate=x+2
  total cost=12
  cost of one dozen chocolate(C2)=(12/(x+2))*12=144/(x+2)
  
  it is given that C1-1=C2 (since cost per dozen is reducing by 1)
  solving the two equations will give us x=16
  
  BUT our answer should be x+2 because that's what she is getting in the end
  so she recieved 18 chocolates
• 7 years agoHelpfull: Yes(8) No(1)
• let no. of chocolates=x=x/12dozen
  price of x/12 dozen is rs 12
  so price of 1 dozen is 144/x
  2nd condition
  (144/x) - (144/(x+2)) = 1
  solving this, we get x as 16. But i bargained and got extra two chocolates so x+2 as answer. so, 16+2 is 18. which leads option D)18 as the correct answer.
• 8 years agoHelpfull: Yes(6) No(3)
• 16;
  (144/x)=(144/x+2)+1;
  x=16,-18
  hence 16 chocolates
• 9 years agoHelpfull: Yes(5) No(3)
• option D,cost of 18 choclates is rs 12,
  cost of 1 choclate =12/18
  cost of 12 choclates=(12/18)*12= 8
  cost of 16 choclates=12
  cost of 1 choclate=12/16
  cost of 12 choclates=(12/16)*12=9
  a/c question,9-8=1
  
• 9 years agoHelpfull: Yes(5) No(7)
• c)14
  1 rupees per 1choclate and two extra means 14
• 9 years agoHelpfull: Yes(4) No(7)
• D.18 chocolets, then cost of each chocolate is 12/18=0.6666 then cost of dozen(12) chocolates is 0.6666*12=8
  
  at first 18-2=16 chocolates then cost of each is 12/16=0.75 then cost of 12 chocolates is 12*0.75=9
  9-8=1
  so answer is 18 chocolates
• 9 years agoHelpfull: Yes(3) No(2)
• No of chocolates-->x or x/12 dozen
  so prize of x/12 =rs 12
  so 1 doz=144/x
  
  also,
  (144/x+2)=(144/x)-1
  
  whih gives x=16
  
• 9 years agoHelpfull: Yes(3) No(0)
• 144/n-144/n+2=1
  the above equation satisfies only by replacing n by 16,
  but the question was how many chocolates i received for 12 rupees so ans is 16+2=18
• 8 years agoHelpfull: Yes(3) No(0)
• buys a/12 chocolates for rs.12
  bargained and buy extra 2 for ever for ones= 144/(a+2)
  which reduces cost by 1 rs=144/(a+2)-1
  144/a=144/(a+2)-1
  a=16
• 8 years agoHelpfull: Yes(2) No(1)
• let us assume cost of 'x' chocolates is 12Rs/-
  => cost of each chocolate = 12/x
  But I took ' x+2 ' chocolates for 12 Rs/-
  => I gave (12/x+2) Rs/- for each chocolate
  Given that I bought dozen chocolates 1 Rupee less than the actual cost of dozen
  12(12/x+2)=12(12/x)-1
  on solving
  x(x+2)=288
  = 16*18
  => x=16
  
• 7 years agoHelpfull: Yes(2) No(0)
• b
  if he initially gets 16 chocolate so cost of 1 dozen is 9
  now he gets 18 chocolates so cost of 1 dozen is 8
  
• 9 years agoHelpfull: Yes(1) No(3)
• 14 chocolates i think am i crct.
  let us assume bunch of chocolates=x
  therefore x chocolates=12 Rs
  bt bargainedhe get x+2 chocolates
  so he gives 1 rs less per dozen than the previous prize i.e 12
  so 12 chocolates=11RS
  
• 9 years agoHelpfull: Yes(1) No(2)
• let x chocolates/12 rs.
  so 12 chocolates-144/x rs.next step
  144/x-1 rs. 12 chocolates.(now)so, 12 rs. now 144x/(144-x) chocolates
  144x/(144-x) - x =2..
  after solved this above equation we get x=16
  
  
• 9 years agoHelpfull: Yes(1) No(1)
• Let the number of chocolates bought = n or n/12 dozens
  Assume this would cost x rupees.
  Now given that (n+2)/12 dozens cost x - 1 rupee.
  So 12/n/12=x - - - (1)
  and 12/(n+2)/12=x−1 - - - (2)
  (1) - (2) = 144/n−144/(n+2)=1
  From the options, 16 satisfies.
• 8 years agoHelpfull: Yes(0) No(0)