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Numerical Ability
Clocks and Calendars
1. Using the digits 1,,4,8 four digit numbers are formed and the sum of all possible such numbers.
Read Solution (Total 12)
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- 27(1+4+8+10+40+80+100+400+800+1000+4000+8000)=389961
- 10 years agoHelpfull: Yes(5) No(10)
- 1 number is missing in the question ,I think!!
- 10 years agoHelpfull: Yes(2) No(0)
- need explaination sos...
- 10 years agoHelpfull: Yes(1) No(0)
- no of digit 3, we can repeat , so possible way .....3^3=27..........and sum of these no =27(unit place nos+10*unit+100*unit+1000*unit);
- 10 years agoHelpfull: Yes(1) No(0)
- How you got 27?
- 10 years agoHelpfull: Yes(0) No(2)
- question asked about four digit number
- 10 years agoHelpfull: Yes(0) No(0)
- Answer is : 389961
- 10 years agoHelpfull: Yes(0) No(0)
- pls expain how u got dat
- 10 years agoHelpfull: Yes(0) No(0)
- please explain
- 10 years agoHelpfull: Yes(0) No(0)
- please expain clearly
- 10 years agoHelpfull: Yes(0) No(0)
- pls give me explanation
- 10 years agoHelpfull: Yes(0) No(0)
- ans will be 81 since repetition is allowed so 3*3*3*3=81
- 10 years agoHelpfull: Yes(0) No(0)
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