1. Using the digits 1,,4,8 four digit numbers are formed and the sum of all possible such numbers.

• 27(1+4+8+10+40+80+100+400+800+1000+4000+8000)=389961
• 9 years agoHelpfull: Yes(5) No(10)
• 1 number is missing in the question ,I think!!
• 9 years agoHelpfull: Yes(2) No(0)
• need explaination sos...
• 9 years agoHelpfull: Yes(1) No(0)
• no of digit 3, we can repeat , so possible way .....3^3=27..........and sum of these no =27(unit place nos+10*unit+100*unit+1000*unit);
• 9 years agoHelpfull: Yes(1) No(0)
• How you got 27?
• 9 years agoHelpfull: Yes(0) No(2)
• question asked about four digit number
  
• 9 years agoHelpfull: Yes(0) No(0)
• Answer is : 389961
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• pls expain how u got dat
  
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• please explain
  
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• please expain clearly
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• pls give me explanation
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• ans will be 81 since repetition is allowed so 3*3*3*3=81
  
• 9 years agoHelpfull: Yes(0) No(0)