CTS
Company
Numerical Ability
Data Sufficiency
4. 2,3,6,7--- using these numbers form the possible four digit numbers that are divisible by 4.
Read Solution (Total 12)
-
- 6732
7632
2736
7236
6372
3672
2376
3276 - 10 years agoHelpfull: Yes(13) No(1)
- if no are repeated
4C2(for 32 being last 2 digits)
4C2(for 36 being last 2 digits)
4C2(for 72 being last 2 digits)
4C2(for 76 being last 2 digits)
so 4*4C2=24
if repetition not allowed
2 ways for 32 being last 2 digits -->6732,7632
2 ways for 36 being last 2 digits--> 2736,7236
2 ways for 72 being last 2 digits--> 3672,6372
2 ways for 76 being last 2 digits--> 3276,2376
- 10 years agoHelpfull: Yes(7) No(0)
- Divisible by 4 means last 2 digits should divisible by 4
2376
3276
6732
7632
3672
6372
total 6 - 10 years agoHelpfull: Yes(6) No(11)
- the digits divisible by 4 are 72,76,36,32. - - - - so the last 2 digits we can arrange 4 ways and the remaining 2 place we can arrange 2 1 so total 4*2=8 ways
- 9 years agoHelpfull: Yes(5) No(0)
- if repeatation allowed ans=24
if not ans=16
last 2 digits should divisible by 4
--32
--36
--72
--76
if repeatation allowed
then selecting two digits from given four digits
4*4c2=24
if not
then selecting two digits from remaining two digits
2*2*2*2=16 - 10 years agoHelpfull: Yes(2) No(2)
- 3672 is the answer.
- 10 years agoHelpfull: Yes(1) No(1)
- if we take last 2 digits as 36 then der vil b 4x4 =16 no. possible..similarly in case of 32, 72 and 76...
so total 16x4=64 no. possible.. - 9 years agoHelpfull: Yes(1) No(0)
- 8 only without repitition
- 8 years agoHelpfull: Yes(1) No(0)
- 36
since there are 6 pairs of no. which are divisible by 4 ; 76 , 72 , 64 , 36 , 32 , 24 and possible ways of filling the hundredth and thousand place is 3 * 2 so total no. of ways = 6 * 3 * 2 - 10 years agoHelpfull: Yes(0) No(1)
- 4,8,........100;
tn=a+(n-1)d
100=4+(n-1)4
96=4n-4
96+4=4n
100/4=n
n=25 - 10 years agoHelpfull: Yes(0) No(2)
- total given numbers 4.
divisible 4 means last 2 digits must divisible by 4
that last 2 digits together taking single digit total 3 parts of that number can be arranged by 3!=3*2*1=6 numbers are formed. - 10 years agoHelpfull: Yes(0) No(1)
- 8 numbers...
- 9 years agoHelpfull: Yes(0) No(0)
CTS Other Question