4. 2,3,6,7--- using these numbers form the possible four digit numbers that are divisible by 4.

• 6732
  7632
  2736
  7236
  6372
  3672
  2376
  3276
• 9 years agoHelpfull: Yes(13) No(1)
• if no are repeated
  4C2(for 32 being last 2 digits)
  4C2(for 36 being last 2 digits)
  4C2(for 72 being last 2 digits)
  4C2(for 76 being last 2 digits)
  so 4*4C2=24
  if repetition not allowed
  2 ways for 32 being last 2 digits -->6732,7632
  2 ways for 36 being last 2 digits--> 2736,7236
  2 ways for 72 being last 2 digits--> 3672,6372
  
  2 ways for 76 being last 2 digits--> 3276,2376
  
• 9 years agoHelpfull: Yes(7) No(0)
• Divisible by 4 means last 2 digits should divisible by 4
  2376
  3276
  6732
  7632
  3672
  6372
  total 6
• 9 years agoHelpfull: Yes(6) No(11)
• the digits divisible by 4 are 72,76,36,32. - - - - so the last 2 digits we can arrange 4 ways and the remaining 2 place we can arrange 2 1 so total 4*2=8 ways
• 9 years agoHelpfull: Yes(5) No(0)
• if repeatation allowed ans=24
  if not ans=16
  
  last 2 digits should divisible by 4
  --32
  --36
  --72
  --76
  if repeatation allowed
  then selecting two digits from given four digits
  4*4c2=24
  
  if not
  then selecting two digits from remaining two digits
  2*2*2*2=16
• 9 years agoHelpfull: Yes(2) No(2)
• 3672 is the answer.
• 9 years agoHelpfull: Yes(1) No(1)
• if we take last 2 digits as 36 then der vil b 4x4 =16 no. possible..similarly in case of 32, 72 and 76...
  so total 16x4=64 no. possible..
• 8 years agoHelpfull: Yes(1) No(0)
• 8 only without repitition
  
• 7 years agoHelpfull: Yes(1) No(0)
• 36
  since there are 6 pairs of no. which are divisible by 4 ; 76 , 72 , 64 , 36 , 32 , 24 and possible ways of filling the hundredth and thousand place is 3 * 2 so total no. of ways = 6 * 3 * 2
• 9 years agoHelpfull: Yes(0) No(1)
• 4,8,........100;
  tn=a+(n-1)d
  100=4+(n-1)4
  96=4n-4
  96+4=4n
  100/4=n
  n=25
• 9 years agoHelpfull: Yes(0) No(2)
• total given numbers 4.
  divisible 4 means last 2 digits must divisible by 4
  that last 2 digits together taking single digit total 3 parts of that number can be arranged by 3!=3*2*1=6 numbers are formed.
• 9 years agoHelpfull: Yes(0) No(1)
• 8 numbers...
  
• 8 years agoHelpfull: Yes(0) No(0)