J is faster than P. J and P each walk 24 km. Sum ofthe speeds of J and P is 7 kmph. Sum of time taken by them is 14 hours. Then J speed is equal to

• let j's speed is x then p's speed would be 7-x.
  and given,
  sum of time taken by them is 14 hours
  =>(24/x)+(24/(7-x)=14
  =>x=4,3
  therefore j's speed will be 4 as j walks faster than p.
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• we have to check through options and 4 kmph is the answer
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• let jake speed be x
  then pauls speed (7-x)
  we are given total time 14 hrs
  
  24/x + 24/(7-x) = 14
  solve the equation
  x= 4 and x = 3
  jake is faster so jake's speed is 4km/hr
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• is this question come in recent tcs exam?
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• 24/t1+24/t2=7
  t1t2=48
  t1+t2=14
  t1=6,t2=8
  j speed=24/6=4km/hr
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• (24/x)+(24/7-x)=14
  by using hit and trail... 6+8=14....
  so x comes out to be 4....
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• Can anyone plz send me latest. . .TCS verbal test questions
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• speed of j is x
  speed of p is 7-x
  then,
  24/x+24/7-x=14
  x`2-7x+12=0
  x=3,4
  since,speed of j is greater,4km/hr is ANS.
  
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• speed of j 4kmph
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• Priyanka..TCS does not ask verbal..
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