Three distinct single digit no A,B,C are in G.P. If abs(x) for real x is the absolute value of x(x if x is positive or zero, and x if x is negative),then the no. of different possible values of abs(A+B-C) is
options
6
4
3
5

• ans 5
  if a=1,r=2 then a=1,b=2,c=4 then abs(a+b-c)=1
  if a=1,r=3 then a=1,a=3,a=9 then abs(1+3-9)=5
  if a=2,r=2, then a=2,b=4,c=8 then abs(2+4-8)=2
  if a=1,r=-2 then a=1,b=-2,c=4 the abs(1-2-4)=5
  if a=1,r=-3 then a=1,b=-3,c=9 then abs(1-3-9)=11
  if a=2,r=-2 then a=2,b=-4,c=-8 then abs(2-4-8)=10
  
  so total 5 abs() values
• 9 years agoHelpfull: Yes(21) No(5)
• is this question recently asked in tcs???
• 9 years agoHelpfull: Yes(5) No(9)
• possible a,b,c are
  1,-3,9
  1,-2,4
  1,2,4
  1,3,9
  (1-3-9),(1-2-4),(1+2-4),(1+3-9)abs values are 11,5,1,5 respectively.
  so ans might be 3
• 9 years agoHelpfull: Yes(0) No(1)
• possible ABC are
  1 3 9
  1 2 4
  2 4 8
  1 -3 9
  1 -2 4
  
  2 -4 8
  so possible values of A+B-C are
  1 2 5 10 11
  so possible ans is 5
  
• 9 years agoHelpfull: Yes(0) No(0)
• d)4-ans.
  A,B,C may be
  (1,2,4) & (4,2,1)
  (1,3,9) & (9,3,1)
  (2,4,8) & (8,4,2)
  (4,6,9) & (9,6,4)
  
  find abs(A+B+C) for these 8 GPs
  7,13,15,19
  
  So,we get 4 different values
• 6 years agoHelpfull: Yes(0) No(0)