In how many ways can 7 different objects be dived among 3 persons so that either one or two of them do not get any object?

a. 381
b. 180
c. 36
d. 84

• case 1: for all obj are given to one person 3
  case 2: choose two out of 3 3c2=3
  naw no of ways to distribute 7 obj to two person=2^7
  sub two way when no obj is given to both
  so no of ways=3+3c2(2^7-2)=381
• 10 years agoHelpfull: Yes(19) No(2)
• case 1: when one of them do not get any object, then the objects will be divided among 2 persons.
  no. of ways to select 2 persons= 3c2.
  no. of ways to divide 7 objects among 2 persons= 2^7.
  so required no. of ways= 3c2(2^7-2) = 378 [when none of them get any object]
  
  case 2: when objects are given to only one person.
  reqd. no. of ways= 3c1 =3.
  so, total no. of ways = 378+3 = 381
• 10 years agoHelpfull: Yes(8) No(0)
• is this corect way of answe total 7c3-(7c1+7c2)
• 10 years agoHelpfull: Yes(6) No(4)
• can u xplain that why 2 is subtracting
• 10 years agoHelpfull: Yes(6) No(2)
• 381
  as per first and second condition
  (3*2^7)-3
• 10 years agoHelpfull: Yes(1) No(2)
• ans- (7+3-1)C(3)=84
• 10 years agoHelpfull: Yes(0) No(5)